我有我想用看我的报告,我可以输入日期后得到两个表。
这里是我的表:客户 - customer_date,姓氏,名字
提供服务 - room_number,date_in,date_out
这里是我的代码现在:它似乎无法从我的表中获取任何行
<?php
$conn = mysql_connect("localhost","root","");
mysql_select_db('irm',$conn);
if(isset($_GET['Submit'])){
$customer_date = $_GET['customer_date'];
}
?>
<form method="get">
<table width="252" border="0">
<tr>
<td width="98">Choose Date:</td>
<td width="144"><label>
<input onclick="ds_sh(this);" name="customer_date" id="customer_date" readonly="readonly" style="cursor: text" />
</label></td>
</tr>
<tr>
<td align="right"><input type="submit" value="Submit" /></a></td>
<td></td>
</tr>
</table>
</form>
<form>
<?php
$tryshow = "SELECT * FROM customers,services WHERE customer_date = '$customer_date' ";
$result = @mysql_query($tryshow,$conn)
or die("cannot view error query");
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print...";
}
while($row=mysql_fetch_assoc($result)){
?>
<table width="700" border="0">
<tr>
<td width="100">Customer Date:</td>
<td width="100">Last Name</td>
<td width="100">First Name</td>
<td width="100">Room Number</td>
<td width="100">Date In</td>
<td width="100">Date Out</td>
</tr>
<tr>
<td><?php echo $row["customer_date"]; ?></td>
<td><?php echo $row['lastname']; ?></td>
<td><?php echo $row['firstname']; ?></td>
<td><?php echo $row['room_number']; ?></td>
<td><?php echo $row['date_in']; ?></td>
<td><?php echo $row['date_out']; ?></td>
</tr>
</table>
<?php }?>
</form>
有了这个,我可以得到谁在这一天会检查任何客户的报告。
我需要一些建议。 希望你能很快回答我。