How do you change a Windows shortcut using Python?
e.g. from:
H:\My Music\some_file.mp3
to:
D:\Users\Myself\My Music\some_file.mp3
How do you change a Windows shortcut using Python?
e.g. from:
H:\My Music\some_file.mp3
to:
D:\Users\Myself\My Music\some_file.mp3
Here's another, more appropriate way to do this in Python with Winshell library: Using Python to create Windows shortcuts. In your case the code will look like:
import os, winshell
from win32com.client import Dispatch
desktop = winshell.desktop()
path = os.path.join(desktop, "some_file.mp3.lnk")
target = r"D:\Users\Myself\My Music\some_file.mp3"
wDir = r"D:\Users\Myself\My Music"
icon = r"D:\Users\Myself\My Music\some_file.mp3"
shell = Dispatch('WScript.Shell')
shortcut = shell.CreateShortCut(path)
shortcut.Targetpath = target
shortcut.WorkingDirectory = wDir
shortcut.IconLocation = icon
shortcut.save()
Existing shortcut should be deleted or rewritten. If you need it for batch processing of shortcut files then I think there's some way to read paths from existing shortcuts, but didn't managed to find it.
Jonathan's solution works perfectly. This is the useful function I produced implementing this. Simply pass in the name of the shortcut file (for example "Mozilla Firefox.lnk", it is unnecessary to specify the entire filepath), and the new shortcut destination, and it will be modified.
import os, sys
import pythoncom
from win32com.shell import shell, shellcon
def short_target(filename,dest):
shortcut = pythoncom.CoCreateInstance (
shell.CLSID_ShellLink,
None,
pythoncom.CLSCTX_INPROC_SERVER,
shell.IID_IShellLink
)
desktop_path = shell.SHGetFolderPath (0, shellcon.CSIDL_DESKTOP, 0, 0)
shortcut_path = os.path.join (desktop_path, filename)
persist_file = shortcut.QueryInterface (pythoncom.IID_IPersistFile)
persist_file.Load (shortcut_path)
shortcut.SetPath(dest)
mydocs_path = shell.SHGetFolderPath (0, shellcon.CSIDL_PERSONAL, 0, 0)
shortcut.SetWorkingDirectory (mydocs_path)
persist_file.Save (shortcut_path, 0)
The only dependency is the pywin32 library. Also note that one is able to specify options and arguments in their shortcut destination. To implement, just call:
short_target("shortcut test.lnk",'C:\\') #note that the file path must use double backslashes rather than single ones. This is because backslashes are used for special characters in python (\n=enter, etc) so a string must contain two backslashes for it to be registered as one backslash character.
This example will set the destination of a shortcut on your desktop called "shortcut test" to a shortcut that opens up the file manager in the root directory of the hard drive (C:).
Here is how you can create a shortcut using Windows script host: http://msdn.microsoft.com/en-us/library/fywyxt64
Try to write it to file from Python and run it dynamically.
Yet another method is detailed here
Use the shortcut update example. You can shortcut.GetPath()
, modify it and then use shortcut.SetPath()
method to set it.
The previous answer are perfectly valid however to really complete them I added the code for bulk editing because I suppose you might have a lots of link to edit.
use this if you want to edit many links at once:
import os, sys
import glob
import pythoncom
from win32com.shell import shell, shellcon
def shortcut_target (filename):
link = pythoncom.CoCreateInstance (
shell.CLSID_ShellLink,
None,
pythoncom.CLSCTX_INPROC_SERVER,
shell.IID_IShellLink
)
persist_file = link.QueryInterface (pythoncom.IID_IPersistFile)
persist_file.Load (filename)
#
# GetPath returns the name and a WIN32_FIND_DATA structure
# which we're ignoring. The parameter indicates whether
# shortname, UNC or the "raw path" are to be
# returned. Bizarrely, the docs indicate that the
# flags can be combined.
#
name, _ = link.GetPath (shell.SLGP_UNCPRIORITY)
target = name
target = target.replace('H:\My Music', 'D:\Users\Myself\My Music')
link.SetPath(target)
persist_file.Save(filename, 0)
return name
def shell_glob (pattern):
for filename in glob.glob (pattern):
if filename.endswith (".lnk"):
print shortcut_target(filename)
desktop = "H:\My Music\"
for filename in shell_glob (os.path.join (desktop, "*")):
print filename