XML - 连载后无法反序列化(XML - Can not deserialize after s

我创建一个列表，将其保存为XML（与XmlSerializer的），但我不是成功（尽管所有的网页搜索...）进行反序列化。

我的实体有：

public class basicTxtFile
{
    public string filename;
    public string description;
}

public class fileTools
{
};

public class textboxTool : fileTools    // text box
{
    public string defaultText;
    public bool multiLine;
    public bool browseButton;
};

public class comboboxTool : fileTools   // combo box
{
    public List<string> values = new List<string>();
};

// Must file, can choose tools: textbox and\or combobox
public class mustFiles : basicTxtFile
{
    public List<fileTools> mustTools = new List<fileTools>();
};

public class OptionalFiles : mustFiles
{
    public bool exist;  // checkbox for defualt value - if the file is exist, if not.
};

在我的应用程序箱列表和我手动填充它。这之后，我与此代码保存它：

//  Save list into XML  -   success
XmlSerializer serializer = new XmlSerializer(typeof(List<mustFiles>), new Type[] {typeof(fileTools), typeof(textboxTool), typeof(comboboxTool)});

using (FileStream stream = File.OpenWrite("MustFiles.xml"))
{
    serializer.Serialize(stream, mustTxtFiles);
}

然后我尝试加载XML文件到列表中，但它失败的原因：“有是XML文档中的错误（2,2）”。 和_ 的InnerException =“是没有预料到 。” 虽然 xml文件自动生成。

我的加载代码是：

// Load XML file into list
List<mustFiles> mustTry = new List<mustFiles>();
mustTry = bl.loadXmlIntoList<mustFiles>("MustFiles.xml", "mustFiles");

loadXmlIntoList功能：

public List<T> loadXmlIntoList<T>(string xmlFileName, string xmlElemnetName)
{
    XmlRootAttribute xRoot = new XmlRootAttribute();
    xRoot.ElementName = xmlElemnetName;
    xRoot.IsNullable = true;

    XmlSerializer serializer = new XmlSerializer(typeof(T), xRoot);

    using (FileStream stream = File.OpenRead(xmlFileName))
    {
        List<T> dezerializedList = (List<T>)serializer.Deserialize(stream);
        return dezerializedList;
    }
}

我的问题：我做了什么错？我怎样才能加载XML文件到列表中？

谢谢！

XML文件（即自动生成）看起来是这样的：

<?xml version="1.0"?>
<ArrayOfMustFiles xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <mustFiles>
    <filename>file1.txt</filename>
    <description>desc1</description>
    <mustTools>
      <fileTools xsi:type="textboxTool">
        <defaultText>Default text 01</defaultText>
        <multiLine>false</multiLine>
        <browseButton>false</browseButton>
      </fileTools>
    </mustTools>
  </mustFiles>
  <mustFiles>
    <filename>file2.txt</filename>
    <description>desc2</description>
    <mustTools>
      <fileTools xsi:type="textboxTool">
        <defaultText>Defualt text 02</defaultText>
        <multiLine>true</multiLine>
        <browseButton>true</browseButton>
      </fileTools>
      <fileTools xsi:type="comboboxTool">
        <values>
          <string>Val1</string>
          <string>Val2</string>
          <string>Val3</string>
        </values>
      </fileTools>
    </mustTools>
  </mustFiles>
  <mustFiles>
    <filename>file2.txt</filename>
    <description>desc2</description>
    <mustTools>
      <fileTools xsi:type="textboxTool">
        <defaultText>Defualt text 03</defaultText>
        <multiLine>false</multiLine>
        <browseButton>true</browseButton>
      </fileTools>
      <fileTools xsi:type="comboboxTool">
        <values>
          <string>ComboVal 1</string>
          <string>ComboVal  2</string>
          <string>ComboVal  3</string>
        </values>
      </fileTools>
      <fileTools xsi:type="comboboxTool">
        <values>
          <string>Second ComboVal 1</string>
          <string>Second ComboVal  2</string>
          <string>Second ComboVal  3</string>
        </values>
      </fileTools>
      <fileTools xsi:type="textboxTool">
        <defaultText>Second defualt text 03</defaultText>
        <multiLine>true</multiLine>
        <browseButton>false</browseButton>
      </fileTools>
    </mustTools>
  </mustFiles>
</ArrayOfMustFiles>

更新：我也尝试添加{get; set;} {get; set;}所述的实体，就像这样：

public class basicTxtFile
{
    public string filename{ set; get; }
    public string description{ set; get; }
}

public class fileTools
{ };

public class textboxTool : fileTools
{
    public string defaultText{ set; get; }
    public bool multiLine{ set; get; }
    public bool browseButton{ set; get; }
};

public class comboboxTool : fileTools
{
    public List<string> values { set; get; }
    public comboboxTool()
    {
        values = new List<string>();
    }
};

public class mustFiles : basicTxtFile
{
    public List<fileTools> mustTools { set; get; }
    public mustFiles()
    {
        mustTools = new List<fileTools>();
    }
};

Answer 1:

我不是一个XML专家。什么是你想用（）的XmlRootAttribute在loadXmlIntoList办？

让反序列化的代码看起来更像是它的系列化对应我稍微返工吧：

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        List<mustFiles> mustTxtFiles = new List<mustFiles>();

        mustFiles mf = new mustFiles();
        mf.filename = "filenameA";
        mf.description = "descriptionA";
        textboxTool tbt = new textboxTool();
        tbt.defaultText = "defaultTextA";
        tbt.browseButton = true;
        tbt.multiLine = true;
        mf.mustTools.Add(tbt);
        mustTxtFiles.Add(mf);

        mf = new mustFiles();
        mf.filename = "filenameB";
        mf.description = "descriptionB";
        tbt = new textboxTool();
        tbt.defaultText = "defaultTextB";
        tbt.browseButton = true;
        tbt.multiLine = true;
        mf.mustTools.Add(tbt);
        mustTxtFiles.Add(mf);

        // serialize it
        XmlSerializer serializer = new XmlSerializer(typeof(List<mustFiles>), new Type[] {typeof(fileTools), typeof(textboxTool), typeof(comboboxTool)});
        string xmlFile = System.IO.Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments), "MustFiles.xml");
        using (System.IO.FileStream stream = File.OpenWrite(xmlFile))
        {
            serializer.Serialize(stream, mustTxtFiles);
        }

        // Why not just this?
        // deserialize it 
        //List<mustFiles> mustTry;
        //using (FileStream stream = File.OpenRead(xmlFile))
        //{
        //    mustTry = (List<mustFiles>)serializer.Deserialize(stream);
        //}

        // deserialize it with generic function:
        List<mustFiles> mustTry = loadXml<List<mustFiles>>(xmlFile, new Type[] { typeof(fileTools), typeof(textboxTool), typeof(comboboxTool) });
    }

    public T loadXml<T>(string xmlFileName, Type[] additionalTypes)
    {
        XmlSerializer serializer = new XmlSerializer(typeof(T), additionalTypes);
        using (FileStream stream = File.OpenRead(xmlFileName))
        {
            return (T)serializer.Deserialize(stream);
        }
    }

}

Answer 2:

我想，但忽略了get {}设置{}你序列化的属性或反序列化的方法你造成！

你如果要在系列化使用它们来使用它的属性。有问题，如果你使用它们只能作为字段，而获取并集