Culture sensitive ParseFloat Function in JavaScrip

问题:

Do anyone have suggestion for writing culture sensitive ParseFloat Function in JavaScript, So that when I have a string 100,000.22 in US culture format the parse float function returns 100000.22 whereas if I enter 100.000,22 in Swedish Culture it returns 100000.22 in float?

回答1:

I've improved mwilcox' function to handle values withous separators.

function parseFloatOpts (str) {

     if(typeof str === "number"){
         return str;
     }

     var ar = str.split(/\.|,/);  

     var value = '';
     for (var i in ar) {
         if (i>0 && i==ar.length-1) {
             value += ".";
         }
         value +=ar[i];
     }
     return Number(value);
}

回答2:

This is a bit rough-and-ready, but it may be sufficient, allowing you to pass in the thousands and decimal separators:

function parseFloatOpts(num, decimal, thousands) {
    var bits = num.split(decimal, 2),
        ones = bits[0].replace(new RegExp('\\' + thousands, 'g'), '');
        ones = parseFloat(ones, 10),
        decimal = parseFloat('0.' + bits[1], 10);
        return ones + decimal;
}

Examples:

parseFloatOpts("100.000,22", ',', '.'); //100000.22
parseFloatOpts("100,000.22", '.', ','); //100000.22

NB that this doesn't ensure that the thousands separator really does represent thousands, etc., or do lots of other safeguarding that you may wish to do, depending on the importance of the function.

回答3:

var parse = function(st){
   if(st.indexOf(",") === st.length-3){
      st = st.replace(".", "").replace(",", ".");
   }else{
       st = st.replace(",", "");
   }
   return parseFloat(st, 10)
}

console.log(parse("100,000.22")) // 100000.22
console.log(parse("100.000,22")) // 100000.22

I'm just checking if there is a comma in the 3rd-to-last position. This could be further refined to check if there is a period in the 4th to last position in the case thee is no comma (such as 100.000)

回答4:

Looking at lonesomday's gave me this thought:

You could also do:

function parse (str)
    var ar = str.split(/\.|,/);  
    return Number(ar[0]+ar[1]+"."+ar[3]);

回答5:

Here is a rough function. It will assume the last punctuation to indicate decimals, whether it is a comma, period, or any other character you may need to indicate. It then eliminates other punctuations from the whole number. Puts it back together and parses as float.

function normalizeFloat(number, chars) {

    var lastIndex = -1;
    for(i=0; i < chars.length; i++) {
        t = number.lastIndexOf(chars[i]);

        if (t > lastIndex) {
            lastIndex = t;
        }
    }

    if (lastIndex == -1) {
        lastIndex = number.length;
    }

    var whole = number.substring(0, lastIndex);   
    var precision = number.substring(lastIndex);
    for (i=0; i < chars.length; i++) {
        whole = whole.replace(chars[i], '');
        precision = precision.replace(chars[i],'.');           
    }
    number = whole + precision;

    f = parseFloat(number);
    return f;
}

try this:

alert(normalizeFloat('12.345,77', [',','.']).toFixed(2));
alert(normalizeFloat('12,345.77', [',','.']).toFixed(2));