可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试):

问题:

The basic idea is that I have a bunch of div's in which each can be toggled (show/hide).

When one div is toggled I'd like for other div's that are currently being shown to hide, thus only allowing one single div to be shown at a time.

In addition I'd like to be able to click outside the element to hide the open div as well.

Just to make things clearer I provided an example which currently does everything I want except closing a div when opening another (Only one div open at a time functionality):

$(document).ready(function(){

  $('div.dropdown').each(function() {
    var $dropdown = $(this);

    $("a.dropdown-link", $dropdown).click(function(e) {
      e.preventDefault();
      $("div.dropdown-container", $dropdown).toggle();
      return false;
    });

});
    
  $('html').click(function(){
    $("div.dropdown-container").hide();
  });
     
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

回答1:

You basically just need to hide all divs except the one being toggled:

$(document).ready(function(){

  $('div.dropdown').each(function() {
    var $dropdown = $(this);

    $("a.dropdown-link", $dropdown).click(function(e) {
      e.preventDefault();
      $div = $("div.dropdown-container", $dropdown);
      $div.toggle();
      $("div.dropdown-container").not($div).hide();
      return false;
    });

});
    
  $('html').click(function(){
    $("div.dropdown-container").hide();
  });
     
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

回答2:

Try the following:

$(document).ready(function(){

  $("a.dropdown-link").click(function(e) {
    e.preventDefault();
    var $div = $(this).next('.dropdown-container');
    $(".dropdown-container").not($div).hide();
    if ($div.is(":visible")) {
        $div.hide()
    }  else {
       $div.show();
    }
});

   $(document).click(function(e){
       var p = $(e.target).closest('.dropdown').length
       if (!p) {
          $(".dropdown-container").hide();
       }
   });

});

DEMO

回答3:

I made it as short as possible! Happy coding!

$(document).ready(function(){
  $(document).on("click", "a", function(event){
    $(this).siblings().show()
    $(this).parent().siblings().each(function(index,element){
       $(element).find(".dropdown-container:visible").hide();
    });
  });
});

Demo: http://jsfiddle.net/NFTFw/60/

回答4:

You can use by smart and easy way to implement by using below code :

<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

$(document).ready(function(){

 $(".dropdown-link").click(function(){
 $(".dropdown-container").slideUp('slow')
 $(this).closest('.dropdown').find('.dropdown-container').slideDown('slow');
 
 });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

Working example Link : http://jsfiddle.net/NFTFw/1901/

回答5:

Here you go:

$("a.dropdown-link", $dropdown).click(function(e) {
  e.preventDefault();
  $(".dropdown-container").hide();
  $("div.dropdown-container", $dropdown).toggle();
  return false;
});

Note the added line:

$(".dropdown-container").hide();

We just hide all the things before toggling the div we want.

回答6:

    $(document).ready(function(){

      $('div.dropdown').each(function() {
        var $dropdown = $(this);

        $("a.dropdown-link", $dropdown).click(function(e) {
          e.preventDefault();
          $("div.dropdown-container").hide();
            if($("div.dropdown-container", $dropdown).hide()){
                $("div.dropdown-container", $dropdown).show();
            }else{
                $("div.dropdown-container", $dropdown).hide();
            }
          return false;
        });

    });

      $('html').click(function(){
        $("div.dropdown-container").hide();
      });

    });

http://jsfiddle.net/NFTFw/40/

回答7:

This code should do the trick, without the use of additional libraries. :)

http://jsfiddle.net/NFTFw/42/

$(document).ready(function(){

  var dd = $(".dropdown-container");

  $("a.dropdown-link").click(function(e) {
    e.preventDefault();
    e.stopPropagation();
    dd.hide();
    $(this).next().show();
  });

  $(document).click(function() {
    dd.hide();
  });

  dd.click(function(e) {
    e.stopPropagation();
  });
});