Pascal's Triangle Format

问题:

The assignment is to create Pascal's Triangle without using arrays. I have the method that produces the values for the triangle below. The method accepts an integer for the maximum number of rows the user wants printed.

public static void triangle(int maxRows) {
    int r, num;
    for (int i = 0; i <= maxRows; i++) {
        num = 1;
        r = i + 1;
        for (int col = 0; col <= i; col++) {
            if (col > 0) {
                num = num * (r - col) / col;    
            }
            System.out.print(num + " ");
        }
        System.out.println();
    }
}

I need to format the values of the triangle such that it looks like a triangle:

              1
            1   1
          1   2   1
        1   3   3   1
      1   4   6   4   1
    1   5  10  10   5   1
  1   6  15  20  15   6   1

I can't for the life of me figure out how to do that. Please answer keeping in mind that I'm a beginner in Java programming.

回答1:

public static long pascalTriangle(int r, int k)
{
    if(r == 1 || k <= 1 || k >= r) return 1L;
    return pascalTriangle(r-1, k-1) + pascalTriangle(r-1, k);
}

This method allows you to find the kth value of rth row.

回答2:

This is a good start, where it's homework, I'll leave the rest to you:

int maxRows = 6;
int r, num;
for (int i = 0; i <= maxRows; i++) {
    num = 1;
    r = i + 1;
    //pre-spacing
    for (int j = maxRows - i; j > 0; j--) {
        System.out.print(" ");
    }
    for (int col = 0; col <= i; col++) {
        if (col > 0) {
            num = num * (r - col) / col;
        }
        System.out.print(num + " ");
    }
    System.out.println();
}

回答3:

In each row you will need to print:

• n spaces
• m numbers
• n spaces

Your job is to figure out n (which will be zero in the last line) and m based on row number.

[This is more like a comment but I needed more formatting options than comments provide]

回答4:

You need to print the spaces (like others have mentioned) and also as this is homework I'm leaving it to you but you might want to look at this handy little function

System.out.printf();

Here is a handy reference guide

Also note that you will need to take into account that some numbers are more than 1 digit long!

回答5:

import java.util.*;
class Mine
{
    public static void main(String ar[])
    {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        for(int i=1;i<n;i++)
        {
            int size=1;
            for(int j=1;j<=i;j++)
            {
                int a[]=new int[size];
                int d[]=new int[size];
                for(int k=1;k<=size;k++)
                {
                    a[1]=1;
                    a[size]=1;

                    for(int p=1;p<=size;p++)
                    {
                        d[p]=a[p];
                    }

                    if(size>=3)
                    {
                        for(int m=2;m<size;m++)
                        {
                            a[m]=d[m]+d[m-1];
                        }
                    }
                }

                for(int y=0;y<size;y++)
                {
                    System.out.print(a[y]);
                }
                System.out.println(" ");
            }
            ++size;
        }
    }
}

回答6:

public class HelloWorld{

     public static void main(String []args){
       int s=7;
       int k=1;
       int r;

       for(int i=1;i<=s;i++){
           int num=1;
           r=i;
           int col=0;
           for(int j=1;j<=2*s-1;j++){

               if(j <= s-i)
               System.out.print("  ");
               else if(j >= s+i)
               System.out.print("  ");
               else{
                   if(k%2 ==0){
                       System.out.print("  ");

                   }
                   else{
                        if (col > 0) {
                            num = num * (r - col) / col;    
                        }

                    System.out.print(num+" ");
                       col++;
                   }
               k++;
               }
           }
           System.out.println("");
           k=1;
       }




     }
}

回答7:

You can try this code in java. It's simple :)

public class PascalTriangle {

public static void main(String[] args) {
    int rows = 10;

    for(int i =0;i<rows;i++) {
        int number = 1;
        System.out.format("%"+(rows-i)*2+"s","");
        for(int j=0;j<=i;j++) {
             System.out.format("%4d",number);
             number = number * (i - j) / (j + 1);

        }
        System.out.println();
    }
  }
}

回答8:

public static void main(String[] args)
{
    int a, num;

    for (int i = 0; i <= 4; i++) 
    {
        num = 1;
        a = i + 1;

        for(int j=4;j>0;j--)
        { 
            if(j>i)
                System.out.print(" ");
        }

        for (int j = 0; j <= i; j++) 
        {
            if (j > 0) 
                num = num * (a - j) / j;   

            System.out.print(num + " ");
        }
        System.out.println();
    } 
}

Code perfectly prints pascal triangle