我在我的数据库图像不被张贴在我的网站(PHP MySQL的)(My image in my data

2019-10-28 10:28发布

所以我创造了一种形式,采用两个文件的按钮(图像)一个缩略图,另一个用于主图像,它已经成功地采取了文件,并把它放在数据库中,它也得到了正确的目录...但是我有一个问题...当它的时间来呼应他们不露面的图片...一些请帮助我

这里是形式和代码(都在叫addimage.php相同的文件):

<?php
include'includes/connect.php';

if($_POST['submit'])
 {
$img="main/";
$img= $img . basename($_FILES['photo1']['name']);

$tmb="thumb/";
$tmb= $tmb . basename($_FILES['photo2']['name']);


$imagename = mysql_real_escape_string($_POST['imagename']);
$content = mysql_real_escape_string($_POST['content']);
$links = mysql_real_escape_string($_POST['links']);
$pic1 = "main/" .(mysql_real_escape_string($_FILES['photo1']['name']));
$pic2 = "thumb/" .(mysql_real_escape_string($_FILES['photo2']['name']));

if(move_uploaded_file($_FILES['photo1']['tmp_name'], $img));{
    if(move_uploaded_file($_FILES['photo2']['tmp_name'], $tmb));{
{

    mysql_query("INSERT INTO `portweb` ( `imagename`, `content`, `links`, `photo1`, `photo2`)  VALUES('$imagename', '$content', '$links', '$pic1', '$pic2')");
    echo "files upload success";
}
}
}
/*else
{
    echo "upload failed";   
}*/

}

?>

<html>
<head>
<title>upload pictures portfolio web</title>
</head>
<body>
<a href="portweb.php">Back</a>
 <br />
 <form action="addportweb.php" method="post" enctype="multipart/form-data">
 <label>Main Image:</label>
 <input type="file" name="photo1" /><br />
<label>Thumb:</label>
<input type="file" name="photo2" /><br />
<label>Name:</label> <input type="text" name="imagename" class="text_input" maxlength="100" /><br />
<label>Description:</label>
<textarea name="content" style="width: 300px; height:80px; padding: 5px; resize:none;" ></textarea>
<br />

<label>Link:</label> <textarea name="links" style="width: 100px; height:50px; padding: 5px; resize:none;" ></textarea><br />
<input type="submit" name="submit" value="upload" /> 
</form>
</body>
</html>

这里是帮助输出功能...也是我的问题:

function getportweb() {
     $query = mysql_query("SELECT * FROM portweb") or die(mysql_error());
      while($post = mysql_fetch_assoc($query)){

        echo "<img src =".$post['photo1']."/>";
            echo "<br>";

        echo "<img src =" . $post['photo2'] . "/>";
            echo"<br>";

        echo "<p>" . $post['imagename'] . "</p>";
            echo "<br>";
        echo "<p>" . $post['content'] . "</p>";
        echo "<br>";
        echo "<p>" . $post['links'] . "</p>";
            echo "<br>";

        echo "<a href=\"deleteportweb.php?id=" . $post['id'] . "\">Delete</a>";
        echo "<a href=\"editportweb.php?id=" . $post['id'] . "\">Edit</a>";
         echo "<br>";
         } 

}

我想相信这是我的问题

echo "<img src =".$post['photo1']."/>";
                echo "<br>";

            echo "<img src =" . $post['photo2'] . "/>";
                echo"<br>";

但我什么都没......请别人帮

Answer 1:

尝试是这样的:

echo'<img src="'.$post['photo1'].'" />';    


文章来源: My image in my database is not posting on my site (PHP MySQL)