How to break out of while loop in Python?

问题:

I have to make this game for my comp class, and I can't figure out how how break out of this loop. See, I have to play against the "computer," by rolling bigger numbers, and seeing who has the bigger score. But I can't figure out how to "break" from my turn, and transition to the computers turn. I need "Q" (quit) to signal the beginning of the computers turn, but I don't know how to do it.

ans=(R)
while True:
    print('Your score is so far '+str(myScore)+'.')
    print("Would you like to roll or quit?")
    ans=input("Roll...")
    if ans=='R':
        R=random.randint(1, 8)
        print("You rolled a "+str(R)+".")
        myScore=R+myScore
    if ans=='Q':
        print("Now I'll see if I can break your score...")
        break

回答1:

A couple of changes mean that only an R or r will roll. Any other character will quit

import random

while True:
    print('Your score so far is {}.'.format(myScore))
    print("Would you like to roll or quit?")
    ans = input("Roll...")
    if ans.lower() == 'r':
        R = np.random.randint(1, 8)
        print("You rolled a {}.".format(R))
        myScore = R + myScore
    else:
        print("Now I'll see if I can break your score...")
        break

回答2:

What I would do is run the loop until the ans is Q

ans=(R)
while not ans=='Q':
    print('Your score is so far '+str(myScore)+'.')
    print("Would you like to roll or quit?")
    ans=input("Roll...")
    if ans=='R':
        R=random.randint(1, 8)
        print("You rolled a "+str(R)+".")
        myScore=R+myScore

回答3:

ans=(R)
while True:
    print('Your score is so far '+str(myScore)+'.')
    print("Would you like to roll or quit?")
    ans=input("Roll...")
    if ans=='R':
        R=random.randint(1, 8)
        print("You rolled a "+str(R)+".")
        myScore=R+myScore
    else:
        print("Now I'll see if I can break your score...")
        ans = False
        break