batch file test error level

问题:

I'm trying to conditionally run an exe from a batch file conditionally upon another exe executing successfully.

I've tried a few different combinations of IF and ERRORLEVEL but none seem to work

"..\..\..\TeamBuildTypes\Current Branch\DatabaseUpdate.exe" -s localhost\sql2008r2 

IF %ERRORLEVEL% 1(
"..\..\..\TeamBuildTypes\Current Branch\DatabaseUpdate.exe" -s localhost\sql2008
)
Pause

Gives me the error

1( was unexpected at this time.

Where am I going wrong here?

回答1:

IF ERRORLEVEL ... is a special syntax supported since the DOS days, the %ERRORLEVEL% variable support was added in WinNT.

The original syntax is used like this:

call someapp.exe
if errorlevel 1 goto handleerror1orhigher
echo succuess... 

To use the variable, use the normal IF syntax: if %errorlevel%==0 echo success...

Note that %errorlevel% stops working if someone does set errorlevel=foo and it might not get updated for internal cmd.exe commands.

An alternative solution is to use &&:

call someapp.exe && (echo success) || (echo error!)

There are (at least) two known cases where errorlevel is broken and you must use || instead:

• RD/RMDir
• > file redirection

回答2:

Negative errorlevels can create problem. Try something like this:

IF '%ERRORLEVEL%'=='0' GOTO OK