(这个问题继续线程“SSRS MDX报告:使用维列上” ,由@whytheq回答)
这个正确的代码始建于previouse螺纹:
WITH
MEMBER [Measures].[Contacts] AS
IIF([Sales_step].CURRENTMEMBER IS [Sales_step].&[contact], [Measures].[Qnt], null)
MEMBER [Measures].[Clients] AS
IIF([Sales_step].CURRENTMEMBER IS [Sales_step].&[client], [Measures].[Qnt], null)
MEMBER [Measures].[Funded] AS
IIF([Sales_step].CURRENTMEMBER IS [Sales_step].&[funded], [Measures].[Qnt], null)
SELECT {[Measures].[Contacts],
[Measures].[Clients],
[Measures].[Funded]} ON COLUMNS,
NON EMPTY
crossjoin({[City].CHILDREN},
{[Sales_step].CHILDREN}) ON ROWS
FROM ( SELECT ( [Sales_step].MEMBERS ) ON COLUMNS
FROM [SALES_PIPE])
它产生正确的结果:
现在我想,以减少行的数量,以一个[市]维才得到结果,如:
要做到这一点我已经试过2次修改代码:
(1)除去CROSSJOIN:
NON EMPTY
crossjoin({[City].CHILDREN},
{[Sales_step].CHILDREN}) ON ROWS
只有一个[城市]维度:
NON EMPTY [City].CHILDREN ON ROWS
(2)离开交叉连接和提取incapsulate它()FUNC:
Extract(
crossjoin({[City].CHILDREN},
{[Sales_step].CHILDREN}),
[City]) ON ROWS
但是这两个变种给空单元格:
我怎样才能得到短暂的结果只有一个行[市]维度?