umbraco razor - getting fields from content

问题:

I have a 6 items of the same content type "news", in each item I have a field newsIntro. I want to put the fields in specific pages on another page so I need to target a specific field so it may be newsIntro on node 1702. I have tried a few things like

@1720.newsIntro

how do I target a specific field

Thanks

回答1:

There are some great resources you should take a look at while you are learning Razor:

1. Umbraco Razor Feature Walkthrough - An eight part blog post series of many of the new Razor features in Umbraco 4.7 with examples.

2. Razor DynamicNode Cheat Sheet - A PDF of all the properties and methods available to the Razor DynamicNode object (that includes @Model).

3. Cultiv Razor Examples - An Umbraco website that you can download and open with WebMatrix or IIS and see various ways to access properties with Razor.

4. Razor snippets - A compilation of different snippets, examples, etc. from Our Umbraco.

But in answer to your question, to get a property of a specific node you have to get the actual DynamicNode object first, then use the property alias to access the property value. Example:

@{
    //Get the node
    dynamic node = Library.NodeById(1720);

    // Display the property
    @node.newsIntro
}

To access a property from the current page, you simply use Model:

@Model.newsIntro

or

@Model.bodyText

or

@Model.Name

回答2:

First, get an IPublishedContent object from the TypedContent method and then use GetPropertyValue to retrieve the value of the field.

@{
  int nodeId = 1720;
  IPublishedContent contentNode = Umbraco.TypedContent(nodeId);
  var newsIntro = contentNode.GetPropertyValue("newsIntro");
}

<p>@newsIntro</p>

回答3:

With Umbraco 7 I used this code to get property from different pages:

@Umbraco.Content(1720).newsIntro

回答4:

If the content item 1720 is a parent or ancestor of the page where you want to use the value, you can get it recursively like this:

@Umbraco.Field("newsIntro", recursive: true)

回答5:

To get fields from content I have used this:

@{
    var selection = Umbraco.TypedContent(contentId).Children()
                        .Where(x => x.IsVisible())
                        .OrderBy("CreateDate");
}
@foreach(var item in selection){
            @item.GetPropertyValue("fieldName1")
            @item.GetPropertyValue("fieldName2")
            @item.GetPropertyValue("fieldName_N")
}