我有一个名为据帧m1
,类似于下面的一个。 我想创建的线图toSL.share
通过agebucket
,为每个单独的一行time.period
。 我使用ggplot
,而是因为我不断收到一个错误agebucket
不是一个连续变量。
agebucket time.period toSL.share
1 (55,60] X1968.2011 0.018442150
2 (60,65] X1968.2011 0.020610489
3 (65,70] X1968.2011 0.056670699
4 (70,75] X1968.2011 0.065512286
5 (75,80] X1968.2011 0.105771028
6 (80,85] X1968.2011 0.134477048
7 (85,90] X1968.2011 0.186838708
10 (55,60] X1968.1984 0.000000000
11 (60,65] X1968.1984 0.004602551
12 (65,70] X1968.1984 0.003316970
13 (70,75] X1968.1984 0.009582950
14 (75,80] X1968.1984 0.024625690
15 (80,85] X1968.1984 0.059762338
16 (85,90] X1968.1984 0.139377908
19 (55,60] X1985.1995 0.018040380
20 (60,65] X1985.1995 0.009361666
21 (65,70] X1985.1995 0.059075563
22 (70,75] X1985.1995 0.059940681
23 (75,80] X1985.1995 0.092601230
24 (80,85] X1985.1995 0.150035413
25 (85,90] X1985.1995 0.153794013
28 (55,60] X1996.2011 0.028367128
29 (60,65] X1996.2011 0.038737821
30 (65,70] X1996.2011 0.098084541
31 (70,75] X1996.2011 0.111219309
32 (75,80] X1996.2011 0.169499287
33 (80,85] X1996.2011 0.164086942
34 (85,90] X1996.2011 0.215390644
这里是我的代码来创建的情节:
> m1$agebucket <- as.factor(m1$agebucket)
> ggplot(m1, aes(x=agebucket, y=toSL.share, col=time.period)) + geom_line()
而这里的错误:
geom_path: Each group consist of only one observation. Do you need to adjust the group aesthetic?
我不明白的错误。 如何创建此图与ggplot
?