我有一个标签,在列表框,还有在列表框中许多的DataTemplates,每个模板都有一个标签,我无法检索标签从后面的代码在cs文件的内容,数据模板是常见的,但每个标签都有不同它里面的文字,所以,我怎么能检索来自templates.As每个标签值还没有为模板,删除模板selected.so如果用户删除模板删除按钮,里面有列表框少模板,所以如何做我通过标签迭代现在检索值。
这里是模板的代码
<TabItem>
<Canvas Height="700" Width="850">
<Canvas.Resources>
<XmlDataProvider x:Key="Tasks" XPath="tasks"
Source="http://store.tymesheet.com/templates/Software-Developer.xml"/>
<DataTemplate x:Key="tasktemplate1">
<Canvas Height="50" Width="850">
<Label x:Name="tasklabel" Content="{Binding XPath=name}" Height="30"
Width="170" Canvas.Top="10" Canvas.Left="150"
Background="LightGray"/>
<TextBox Height="30" Width="100" Canvas.Top="10"
Canvas.Left="370" Background="AliceBlue"/>
<Label Canvas.Left="500" Canvas.Top="10">$</Label>
<Button Click="deletebuttonclick"
Canvas.Top="12" Height="10" Width="30"
Canvas.Left="600"/>
</Canvas>
</DataTemplate>
</Canvas.Resources>
<ListBox ItemTemplate="{StaticResource tasktemplate1}"
ItemsSource="{Binding Tasks}"
x:Name="tasklistBox" Height="700" Width="850"/>
<Label Canvas.Top="-18" Canvas.Left="185">Select Task</Label>
<Label Canvas.Top="-18" Canvas.Left="377" RenderTransformOrigin="0.58,0.462">Enter Bill Rates</Label>
<Button Click="addtask" Canvas.Left="39" Canvas.Top="575" Width="139">Click to add the task</Button>
</Canvas>
</TabItem>
这里是按钮后面的代码
private void addtask(object sender,RoutedEventArgs e)
{
foreach (ListBoxItem item in tasklistBox.Items)
{
// Getting the ContentPresenter of myListBoxItem
ContentPresenter myContentPresenter = FindVisualChild<ContentPresenter>(item);
// Finding textBlock from the DataTemplate that is set on that ContentPresenter
DataTemplate myDataTemplate = myContentPresenter.ContentTemplate;
System.Windows.Forms.Label mydata = (System.Windows.Forms.Label)myDataTemplate.FindName("tasklabel", myContentPresenter);
// Do something to the DataTemplate-generated TextBlock
System.Windows.MessageBox.Show("element" + mydata);
}
}
在我的cs文件我也加载在XML文件中删除模板。
{
InitializeComponent();
XmlDocument doc = new XmlDocument();
doc.Load("http://store.tymesheet.com/templates/Software-Developer.xml");
var taskList = doc.ChildNodes.OfType<XmlNode>()
.Where(node => node.Name == "tasks")
.SelectMany(node => node.ChildNodes.OfType<XmlNode>());
Tasks = new ObservableCollection<XmlNode>(taskList);
this.DataContext = this;
}
任何帮助,感谢名单。