Interval interval = new Interval(new DateTime("2014-01-01"), new DateTime("2014-01-30"));
有没有办法让这个周末天数？
就像是：
interval.toPeriod.getWeekendDays();
Answer 1:
自定义Iterator
WeekendDayIterator是一个Iterator在周末天Interval规定：
class WeekendDayIterator(interval: Interval) extends Iterator[LocalDate] {
var day = interval.getStart.toLocalDate
private def peek = day.plusDays(1)
def hasNext: Boolean = peek.isBefore(interval.getEnd.toLocalDate)
private def isWeekend(ld: LocalDate): Boolean = ld.getDayOfWeek == SATURDAY || ld.getDayOfWeek == SUNDAY
def next(): LocalDate = { val d = day; do day = peek; while (!isWeekend(day)); d }
}
def weekendLocalDates(interval: Interval): List[LocalDate] = new WeekendDayIterator(interval).toList
// The `LocalDate`s for weekend days
println(weekendLocalDates(new Interval(new DateTime("2013-10-01"), new DateTime("2014-01-30"))))
// The days of year for weekend days
println(weekendLocalDates(new Interval(new DateTime("2013-10-01"), new DateTime("2014-01-30"))).map(_.getDayOfYear))
导致下面的输出：
List(2013-10-01, 2013-10-05, 2013-10-06, 2013-10-12, 2013-10-13, 2013-10-19, 2013-10-20, 2013-10-26, 2013-10-27, 2013-11-02, 2013-11-03, 2013-11-09, 2013-11-10, 2013-11-16, 2013-11-17, 2013-11-23, 2013-11-24, 2013-11-30, 2013-12-01, 2013-12-07, 2013-12-08, 2013-12-14, 2013-12-15, 2013-12-21, 2013-12-22, 2013-12-28, 2013-12-29, 2014-01-04, 2014-01-05, 2014-01-11, 2014-01-12, 2014-01-18, 2014-01-19, 2014-01-25, 2014-01-26)
List(274, 278, 279, 285, 286, 292, 293, 299, 300, 306, 307, 313, 314, 320, 321, 327, 328, 334, 335, 341, 342, 348, 349, 355, 356, 362, 363, 4, 5, 11, 12, 18, 19, 25, 26)
该代码是写在斯卡拉 。 它移植到Java应该直截了当。
Answer 2:
下面是使用乔达时API的Java实现。 你基本上弄清楚的时候是第一个周末，从开始日期，再加入7天，保持在一个循环，直到结束日期之后。 你会收集所有的周末。 诀窍是，如果结束日期是周六，你要停在那里。
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.List;
import org.joda.time.LocalDate;
public class DateUtil {
public static List<String> getWeekends(LocalDate fromDate, LocalDate toDate){
List<String> weekends = new ArrayList<String>();
SimpleDateFormat format = new SimpleDateFormat("MM-dd-yyyy");
int fromDay = fromDate.getDayOfWeek();
int daysToFirstWeekend = 6-fromDay;
LocalDate nextWeekend = fromDate.plusDays(daysToFirstWeekend);
while(nextWeekend.isBefore(toDate)){
weekends.add(format.format(nextWeekend.toDate()));
if(nextWeekend.plusDays(1).isBefore(toDate)){
weekends.add(format.format(nextWeekend.plusDays(1).toDate()));
}
nextWeekend = nextWeekend.plusDays(7);
}
return weekends;
}
public static void main(String[] args){
LocalDate fromDate = new LocalDate();
LocalDate toDate = fromDate.plusDays(45);
System.out.println(getWeekends(fromDate, toDate));
}
}
如果你想从现在开始一切从今天（2016年4月16日）和45日的周末，它会给输出
[04-16-2016, 04-17-2016, 04-23-2016, 04-24-2016, 04-30-2016, 05-01-2016, 05-07-2016, 05-08-2016, 05-14-2016, 05-15-2016, 05-21-2016, 05-22-2016]
文章来源: how to get weekends in an Interval? joda time
