我把所有的Struts的jar
包括在WEB-INF/lib
,并导入到项目。 我试图从迁移基于简单的servlet项目Struts2的。 我添加过滤器标签在web.xml
,并在不断的标签struts.xml
按照教程,但我得到404上的servlet调用。
web.xml
:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>Solution</display-name>
<welcome-file-list>
<welcome-file>Login.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>struts2</filter-name>
<filter-class>
org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<display-name>LoginController</display-name>
<servlet-name>LoginController</servlet-name>
<servlet-class>com.tcs.controller.LoginController</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>LoginController</servlet-name>
<url-pattern>/LoginController</url-pattern>
</servlet-mapping>
</web-app>
struts.xml
:
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<constant name="struts.action.excludePattern" value="/LoginController"></constant>
<package name="default" extends="hibernate-default">
</package>
</struts>
错误JSP页面:
HTTP Status 404 - There is no Action mapped for namespace / and action name LoginController.
The requested resource (There is no Action mapped for namespace / and action name LoginController.) is not available.