我有有列作为一个user_log_table
Userid logintime browsername
1 2013/10/01 00:10:10 Chrome
1 2013/10/01 17:23:10 Chrome
1 2013/10/01 00:30:41 Mozilla
1 2013/10/02 05:10:52 IE
3 2013/10/02 09:10:25 Chrome
3 2013/10/03 10:10:18 Safari
1 2013/10/03 13:10:35 Chrome
我想应该显示输出作为查询
Userid browser 01/10 02/10 03/10
1 Chrome 2 0 1
1 Mozilla 1 0 0
1 IE 0 1 0
3 Chrome 0 1 0
3 Safari 0 0 1
请注意,Browsername是不固定的,它的动态,...
我曾尝试与查询作为
SELECT userid, browser, Day(logintime) as LoginDay, COUNT(logintime) as Num
FROM user_log_table
GROUP BY userid, browser, Day(logintime)
但没有找到的结果,因为我想...我能得到列如上标题,太数据?
我看到这个充满活力的支点问题不同的时间。 而且我也必须这样做。 搜索了很多后,我来taht为我的伟大工程的解决方案。 它不是那么优雅,但它救了我。 我要做的就是先在一个临时表准备数据,在那之后我动态创建枢轴字符串(在你的情况下,它是DD-MM)将其分配给一个变量。 而在最后,我建立一个SQL字符串来执行动态SQL。
我用了你的样本数据,它似乎工作。 希望这可以帮助
select
userid,
browsername,
CAST(day(logintime) as nvarchar(2)) + '-' + CAST(Month(logintime) AS nVARCHAR(2)) AS period
INTO #TMP
from user_log_table order by 1
DECLARE @cols AS NVARCHAR(MAX), @query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ','
+ QUOTENAME(convert(varchar(10), period, 120))
from #TMP order by 1
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT userid, browsername,' + @cols + ' from
(
select userid, browsername, period
from #TMP
) x
pivot
(
count(period)
for period in (' + @cols + ')
) p '
exec(@query)
drop table #TMP
像下面或者你可以使用这个PIVOT在MS SQL:
SQLFiddle演示
SELECT browsername,
SUM(CASE WHEN DAY(logintime) = 1 THEN 1 ELSE 0 END) as [01/10],
SUM(CASE WHEN DAY(logintime) = 2 THEN 1 ELSE 0 END) as [02/10],
SUM(CASE WHEN DAY(logintime) = 3 THEN 1 ELSE 0 END) as [03/10],
...
SUM(CASE WHEN DAY(logintime) = 31 THEN 1 ELSE 0 END) as [31/10]
FROM user_log_table
GROUP BY browsername
DECLARE @cols VARCHAR(100),@SQL VARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' +
QUOTENAME(convert(varchar(10),LoginTime,103))
FROM
user_log_table
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
, 1, 1, '');
SET @SQL = 'SELECT *
FROM
(
SELECT
Userid,
browsername,
convert(varchar(10),LoginTime,103) LoginDay
FROM user_log_table xx
) AS t
PIVOT
(
count(LoginDay)
FOR LoginDay IN( '+@cols+' ) ) AS p ; '
EXEC (@SQL)