我想打电话给在Xcode使用telprompt电话号码“＃51234” [复制](I want to

这个问题已经在这里有一个答案：

在iOS与包括hashtag电话呼叫号码 3回答

我想打电话给在Xcode使用telprompt电话号码“＃51234”。

但telprompt是拒绝。

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"telprompt://#5%@", nzoneNum]]];

nzomeNum是 “1234”

Answer 1:

至少的iOS 11，一个可与包括hashtag（＃）或星号（*）拨号号码。

通过第一编码的电话号码 ，然后加入让这些字符电话tel:前缀，终于打开生成的字符串为URL。

迅速4，11的iOS

// set up the dial sequence
let nzoneNum = "1234"
let prefix = "#5"
let dialSequence = "\(prefix)\(nzoneNum)"

// "percent encode" the dial sequence with the URL Host allowed character set
guard let encodedDialSequence =
    dialSequence.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed) else {
    print("Unable to encode the dial sequence.")
    return
}

// add the `tel:` url scheme to the front of the encoded string
let dialURLString = "tel:\(encodedDialSequence)"

// set up the URL with the scheme/encoded number string
guard let dialURL = URL(string: dialURLString) else {
    print("Couldn't make the dial string into an URL.")
    return
}

// dial the URL
UIApplication.shared.open(dialURL, options: [:]) { success in
    if success { print("SUCCESSFULLY OPENED DIAL URL") }
    else { print("COULDN'T OPEN DIAL URL") }
}

客观-C，11的iOS

// set up the dial sequence
NSString *nzoneNum = @"1234";
NSString *prefix = @"#5";
NSString *dialSequence = [NSString stringWithFormat:@"%@%@", prefix, nzoneNum];

// set up the URL Host allowed character set, and "percent encode" the dial sequence
NSCharacterSet *urlHostAllowed = [NSCharacterSet URLHostAllowedCharacterSet];
NSString *encodedDialSequence = [dialSequence stringByAddingPercentEncodingWithAllowedCharacters:urlHostAllowed];

// add the `tel` url scheme to the front of the encoded string
NSString *dialURLString = [NSString stringWithFormat:@"tel:%@", encodedDialSequence];

// set up the URL with the scheme/encoded number string
NSURL *dialURL = [NSURL URLWithString:dialURLString];

// set up an empty dictionary for the options parameter
NSDictionary *optionsDict = [[NSDictionary alloc] init];

// dial the URL
[[UIApplication sharedApplication] openURL:dialURL
                                   options:optionsDict
                         completionHandler:^(BOOL success) {
                             if (success) { NSLog(@"SUCCESSFULLY OPENED DIAL URL"); }
                             else { NSLog(@"COULDN'T OPEN DIAL URL"); }
                         }];

Answer 2:

不幸的是，你不能让任何号码，包括一个主题标签调用。苹果显然限制了这些电话： iPhoneURLScheme_Reference