Java servlet为：对XSD XML验证(Java servlets: xml valida

我有一个使用打包的.jar归档工具的servlet：

@Override
public void init() throws ServletException {
    ...
    try (InputStream stream = getClass().getResourceAsStream("/fileToParse.xml")) {
        App.check(stream);
    } catch (Exception e) {
        throw new ServletException(e);
    }
    ...
}

此实用程序需要XML文件流，对XSD架构进行验证，并对其进行解析：

public class App {
    private static final String JAXP_SCHEMA_LANGUAGE = "http://java.sun.com/xml/jaxp/properties/schemaLanguage";
    private static final String W3C_XML_SCHEMA = "http://www.w3.org/2001/XMLSchema"; 
    ...   
    public static void check(InputStream stream) {    
        SAXParserFactory spf = SAXParserFactory.newInstance();
        spf.setNamespaceAware(true);
        spf.setValidating(true);
        MyHandler handler = new MyHandler();
        try {
            SAXParser sp = spf.newSAXParser();
            sp.setProperty(JAXP_SCHEMA_LANGUAGE, W3C_XML_SCHEMA);
            XMLReader rdr = sp.getXMLReader();
            rdr.setContentHandler(handler);
            rdr.setErrorHandler(new MyErrorHandler());
            rdr.parse(new InputSource(stream));
        }
        ...
    }
    ...
}

XSD文件的开头为：

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           targetNamespace="http://www.mydomain.org"
           elementFormDefault="qualified"
           xmlns:t="http://www.mydomain.org">
    <xs:element name="appContext">
        ...

xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<appContext xmlns="http://www.mydomain.org"
            xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xsi:schemaLocation="http://www.mydomain.org appContext.xsd">
    ...

的.war结构：

css/
js/
WEB-INF/
    classes/
        mypackage/
            MyServlet.class
        fileToParse.xml
    lib/
        App.jar
    web.xml

App.jar结构：

mypackage2/
    App.class
appContext.xsd

servlet初始化方法抛出异常：

...
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615) [na:1.7.0_21]
    at java.lang.Thread.run(Thread.java:722) [na:1.7.0_21]
Caused by: java.io.FileNotFoundException: /PATH_TO_TOMCAT/bin/appContext.xsd (No such file or directory)
    at java.io.FileInputStream.open(Native Method) ~[na:1.7.0_21]
    at java.io.FileInputStream.<init>(FileInputStream.java:138) ~[na:1.7.0_21]

我怎么能指定的SAXParser是XSD架构需要的地方，以验证XML文件？

PS对不起，我的英语不好

UPD：

我尝试添加该属性：

    private static final String JAXP_SCHEMA_SOURCE =
            "http://java.sun.com/xml/jaxp/properties/schemaSource";
    ....
    public static void check(InputStream stream) {
        ...
        try {
            ...
            sp.setProperty(JAXP_SCHEMA_SOURCE, new File(getPath("/appContext.xsd")));
            ...
        }
    }
    public static String getPath(String path) {
        return App.class.getResource(path).toString();
    }

现在我有这样的例外：

ERROR mypackage2.App - Error: URI=null Line=5: schema_reference.4: Failed to read schema document 'jar:file:/PATH_TO_TOMCAT/webapps/myapp/WEB-INF/lib/App.jar!/appContext.xsd', because 1) could not find the document; 2) the document could not be read; 3) the root element of the document is not <xsd:schema>.
org.xml.sax.SAXParseException: schema_reference.4: Failed to read schema document 'jar:file:/PATH_TO_TOMCAT/webapps/myapp/WEB-INF/lib/App.jar!/appContext.xsd', because 1) could not find the document; 2) the document could not be read; 3) the root element of the document is not <xsd:schema>.
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:198) ~[na:1.7.0_21]

UPD2：随着“类路径：appContext.xsd” xml文件中：

WARN  mypackage.App - Warning: URI=null Line=5: schema_reference.4: Failed to read schema document 'classpath:appContext.xsd', because 1) could not find the document; 2) the document could not be read; 3) the root element of the document is not <xsd:schema>.
org.xml.sax.SAXParseException: schema_reference.4: Failed to read schema document 'classpath:appContext.xsd', because 1) could not find the document; 2) the document could not be read; 3) the root element of the document is not <xsd:schema>.
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:198) ~[na:1.7.0_21]
...
    at java.lang.Thread.run(Thread.java:722) [na:1.7.0_21]
Caused by: java.net.MalformedURLException: unknown protocol: classpath
    at java.net.URL.<init>(URL.java:592) ~[na:1.7.0_21
;;;

Answer 1:

尝试设置模式源为InputStream直接

public static void check(InputStream stream) {
    ...
    try {
        ...
        sp.setProperty(JAXP_SCHEMA_SOURCE, getInputStream("/appContext.xsd")));
        ...
    }
}

public static InputStream getInputStream(String path) {
    return SAXLoader.class.getResourceAsStream(path);
}

检查是否设置该属性删除从XML文件中的XSD引用后的作品。如果没有，检查属性通过简单地定位为一个传递的罐子，它的绝对路径之外的XSD测试工作或没有File引用作为你现在在做什么。

Answer 2:

问题解决了：

public class App {
    ...   
    public static void check(InputStream stream) {    
        SAXParserFactory spf = SAXParserFactory.newInstance();
        spf.setNamespaceAware(true);
        spf.setValidating(true);
        MyHandler handler = new MyHandler();
        try (InputStream schemaStream = App.class.getResourceAsStream("/appContext.xsd")) {
            SAXParser sp = spf.newSAXParser();
            sp.setProperty(JAXPConstants.JAXP_SCHEMA_LANGUAGE, JAXPConstants.W3C_XML_SCHEMA);
            sp.setProperty(JAXPConstants.JAXP_SCHEMA_SOURCE, new InputSource(schemaStream));
            XMLReader rdr = sp.getXMLReader();
            rdr.setContentHandler(handler);
            rdr.setErrorHandler(new MyErrorHandler());
            rdr.parse(new InputSource(stream));
        }
        ...
    }
    ...
}