如何使一个jquery的DataTable阵列不符合标准的JSON？(How to make a j

首先我是一个总的jQuery / JS newbee！
然后，我有很长的JSON是这样的：

[
{
    "rulesrev": 74,
    "macaddr": "",
    "lat": "3543.03133N",
    "ip": "10.128.113.180",
    "clientname": "D-06-29",
    "relay0mask": "-1",
    "relay1stat": "-1",
    "clientid": 542,
    "bldname": "D_valiasr_zartosht",
    "uptime": "",
    "current": "",
    "temperature": "",
    "softver": "",
    "relay0stat": "0",
    "volume": "100",
    "hardver": " ",
    "relay1mask": "-1",
    "pic": "",
    "comment": " p",
    "lon": "05124.48299E",
    "rtt": "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)",
    "bldaddr": ""
},
{
    "rulesrev": 74,
    "macaddr": "00:10:f3:22:30:08,00:10:f3:22:30:09",
    "lat": "3537.41356N",
    "ip": "10.19.64.63",
    "clientname": "M-19-013",
    "relay0mask": "-1",
    "relay1stat": "-1",
    "clientid": 494,
    "bldname": "tarebar_m19",
    "uptime": "19d 20:05:12",
    "current": "",
    "temperature": "",
    "softver": "",
    "relay0stat": "0",
    "volume": "100",
    "hardver": " n",
    "relay1mask": "-1",
    "pic": "",
    "comment": " ",
    "lon": "05122.94431E",
    "rtt": "2012/08/25 09:19:25.0 (load=0.05) (mem=0.17)",
    "bldaddr": ""
}
]

，我想将其转换为一个jQuery数据表可读阵列应该是这样的：

"aaData": [
            /* Reduced data set */
            [ "Trident", "Internet Explorer 4.0", "Win 95+", 4, "X" ],
            [ "Trident", "Internet Explorer 5.0", "Win 95+", 5, "C" ],
            [ "Trident", "Internet Explorer 5.5", "Win 95+", 5.5, "A" ],
            [ "Trident", "Internet Explorer 6.0", "Win 98+", 6, "A" ],
            [ "Trident", "Internet Explorer 7.0", "Win XP SP2+", 7, "A" ],
            [ "Gecko", "Firefox 1.5", "Win 98+ / OSX.2+", 1.8, "A" ],
            [ "Gecko", "Firefox 2", "Win 98+ / OSX.2+", 1.8, "A" ],
            [ "Gecko", "Firefox 3", "Win 2k+ / OSX.3+", 1.9, "A" ],
            [ "Webkit", "Safari 1.2", "OSX.3", 125.5, "A" ],
            [ "Webkit", "Safari 1.3", "OSX.3", 312.8, "A" ],
            [ "Webkit", "Safari 2.0", "OSX.4+", 419.3, "A" ],
        [ "Webkit", "Safari 3.0", "OSX.4+", 522.1, "A" ]
        ],
        "aoColumns": [
            { "sTitle": "Engine" },
        { "sTitle": "Browser" },
            { "sTitle": "Platform" }
]

我该怎么办？
我无法找到任何张贴在这里或其他地方来形容这样的事情谁能帮助？
编辑
第二阵列仅仅是一个结构I中所看到的数据表例子。我想我的JSON更改为结构类的第二阵列
编辑：在我的JSON每个数据的第一部分将使得表列标题将到第二阵列结构的底部和所述第二部分是所述值变为所述第二阵列结构顶部部分。最后它应该是这样的：

      "aaData": [
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""],
[ 74, "", "3543.03133N", "10.128.113.180", "D-06-29", "-1", "-1", 542, "D_valiasr_zartosht", "", "", "", "", "0", "100", "", "-1", "", " p", "05124.48299E", "2012/08/15 23:20:55.0 (load=0.05) (mem=0.11)", ""]
    ],        "aoColumns": [
{ "sTitle": "macaddr" },
{ "sTitle": "lat" },
{ "sTitle": "ip" },
{ "sTitle": "clientname" },
{ "sTitle": "relay0mask" },
{ "sTitle": "relay0stat" },
{ "sTitle": "relay1stat" },
{ "sTitle": "clientid" },
{ "sTitle": "bldname" },
{ "sTitle": "uptime" },
{ "sTitle": "current" },
{ "sTitle": "temperature" },
{ "sTitle": "softver" },
{ "sTitle": "volume" },
{ "sTitle": "hardver" },
{ "sTitle": "relay1mask" },
{ "sTitle": "pic" },
{ "sTitle": "comment" },
{ "sTitle": "lon" },
{ "sTitle": "rtt" },
{ "sTitle": "bldaddr" },
 ] 
 ]

没有什么神奇的方法。你必须通过你的原始对象进行迭代，并创建数据表以期望的格式的对象。

假设你想在表三列

rulesrev，MACADDR，采用

你可以使用下面的代码来生成由数据表所需要的格式的数据http://jsfiddle.net/vZVUc/

var originalJson = [{...}]; // Your JSON blob

// You can't rely on the order of iteration of properties in your JSON object,
// so you have to specify which fields you want
var columns = ["rulesrev", "macaddr", "lat"];

// If you don't care about the order of properties, you can generate columns 
// using the following
var columns = [];
for (var propName in originalJson[0]) {
  columns.push(propName);
}

var dataTableObj = {
   aaData: [],
   aoColumns: []
};

// Stuff the aoColumns array
for (var i=0; i < columns.length; i++) {
    dataTableObj.aoColumns.push({sTitle: columns[i]})
}

// Stuff the aaData array
for (var i=0; i < originalJson.length; i++) {
    var row = originalJson[i];
    var dataTableRow = [];
    for (var j=0; j < columns.length; j++) {
        dataTableRow.push(row[columns[j]]);
    }
    dataTableObj.aaData.push(dataTableRow);
}

// Now you can pass it to your datatable
$('#example').dataTable( dataTableObj );

如果你喜欢冒险，你可以使用Array.map （支持更高版本浏览器而已，但容易地创建一个垫片）。 http://jsfiddle.net/vZVUc/1/

// You can't rely on the order of iteration of properties in your JSON object,
// so you have to specify which fields you want
var columns = ["rulesrev", "macaddr", "lat"];

var dataTableObj = {
   aaData: originalJson.map(function(row) {
      return columns.map(function(col){
          return row[col];
      })
   }) ,
   aoColumns: columns.map(function(col){
      return {sTitle: col}
   });
};

~~这不是测试，所以有可能是错误的，但它应该教你如何做到这一点。~~ 见http://jsfiddle.net/vZVUc/1/和http://jsfiddle.net/vZVUc/的例子