从一个活动图像发送到Android的另一个使用列表视图项(send image from one a

我取出由URL数据到ListView和我想，只要用户点击列表视图项，然后选择项目的详细信息将显示给用户提供图像一起和我对文本数据发送到另一个活动，但无法发送图像，但在singleitem活动我在imageview的越来越空白，而不是形象，我怎么能解决这个problem.Some代码以供参考： -

     ListViewActivity Code:-   

    public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
 // getting values from selected ListItem
String title = ((TextView) view.findViewById(R.id.title)).getText().toString();
String artist = ((TextView) view.findViewById(R.id.artist)).getText().toString();
String duration = ((TextView) view.findViewById(R.id.duration)).getText().
    toString();
String image = ((ImageView)view.findViewById(R.id.list_image))
    .getImageMatrix().toString();

// Starting new intent
Intent in = new Intent(getApplicationContext(), SingleMenuItemActivity.class);
in.putExtra(KEY_TITLE, title);
in.putExtra(KEY_ARTIST, artist);
in.putExtra(KEY_DURATION, duration);
in.putExtra(KEY_THUMB_URL, image);
startActivity(in);

     SingleItemActivity Code:-
    // getting intent data
    Intent in = getIntent();

    // Get XML values from previous intent

    String title = in.getStringExtra(KEY_TITLE);
    String artist = in.getStringExtra(KEY_ARTIST);
    String duration = in.getStringExtra(KEY_DURATION);
    Bitmap bitmap =(Bitmap) in.getParcelableExtra(KEY_THUMB_URL);




    // Displaying all values on the screen
    TextView lblName = (TextView) findViewById(R.id.name_label);
    TextView lblCost = (TextView) findViewById(R.id.email_label);
    TextView lblDesc = (TextView) findViewById(R.id.mobile_label);     
    ImageView image = (ImageView)findViewById(R.id.image_label);
    image.setImageBitmap(bitmap);   


    lblName.setText(title);
    lblCost.setText(artist);
    lblDesc.setText(duration);

     SingleItemXML Code:-
     <LinearLayout
      xmlns:android="http://schemas.android.com/apk/res/android"
      android:orientation="vertical"
      android:layout_width="match_parent"
      android:layout_height="match_parent">

    <ImageView     
        android:id="@+id/image_label"   
        android:layout_width="50dp"
        android:layout_height="50dp"
        android:src="@drawable/rihanna"
        />


        <TextView android:id="@+id/name_label"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:textSize="25dip"
        android:textStyle="bold"
        android:paddingTop="10dip"
        android:paddingBottom="10dip"
        android:textColor="#43bd00"/>

        <TextView android:id="@+id/email_label"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:textColor="#acacac"/>

       <TextView android:id="@+id/mobile_label"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:textStyle="bold"/>

        </LinearLayout>

Answer 1:

您应该使用buildDrawingCache()和getDrawingCache()从ImageView的得到位图，所以在您的onItemClick()做的，

imageView.buildDrawingCache();
Bitmap bitmap = imageView.getDrawingCache();

Intent intent = new Intent(context, next_activity.this);
intent.putExtra("image", bitmap);
startActivity(intent);

因为，在检索下一个活动，

bitmap = getIntent().getParcelableExtra("image");

Answer 2:

in.putExtra（KEY_THUMB_URL，图像）;

将图像转换为BASE64字符串格式。在新的活动转换为BASE64字符串中的图像再次..

public String bitMapToString(Bitmap bitmap) {
        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        bitmap.compress(Bitmap.CompressFormat.PNG, 100, baos);
        byte[] b = baos.toByteArray();
        String stringBody = null;
        try {
            stringBody = Base64.encodeToString(b, Base64.DEFAULT).toString();
        } catch (Exception e) {
            toast(e.toString());
            e.printStackTrace();
        }
        return stringBody;
    }