如何解析内部JSON对象数组(How to parse Inner json objects arr

我与ESPN体育API工作。 任何一个可以帮助我如何解析呢？

我贴我的代码，我能来解析名称和ID，请大家帮忙如何解析内部对象的项目。

public class BaseballActivity extends ListActivity{

private static String url = "http://api.espn.com/v1/sports/baseball?apikey=h29yphwtf7893hktfbn7cd5g";

private static final String TAG_SPORTS = "sports";
private static final String TAG_ID = "id";
private static final String TAG_TIMESTAMP = "timestamp";
private static final String TAG_NAME = "name";
private static final String TAG_NEWS = "news";
private static final String TAG_HEADLINES = "headlines";
private static final String TAG_LINKS = "links";
private static final String TAG_API = "api";
private static final String TAG_SPORTS1 = "sports";
private static final String TAG_HREF = "href";

JSONArray sports = null;

@Override
public void onCreate(Bundle savedInstanceState) {


    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // HashMap for ListView

    ArrayList<HashMap<String, String>> sportsList = new ArrayList<HashMap<String, String>>();

    // creating Json parser instance
    JSONParser jParser = new JSONParser();

    // getting Json String from url

    JSONObject json = jParser.getJSONFromUrl(url);

    try{
        // Getting Array of Contacts
                    sports = json.getJSONArray(TAG_SPORTS);

                    // looping through All Contacts
                    for(int i = 0; i < sports.length(); i++){
                        JSONObject c = sports.getJSONObject(i);


            //String news = c.getString(TAG_NEWS);
           // String headlines = c.getString(TAG_HEADLINES);
            String name = c.getString(TAG_NAME);
           // String timestamp = c.getString(TAG_TIMESTAMP);
            String id = c.getString(TAG_ID);

         //   JSONObject links = c.getJSONObject(TAG_LINKS);
          //  JSONObject api = c.getJSONObject(TAG_API);
          //  JSONObject sports = c.getJSONObject(TAG_SPORTS1);

         //   String href = c.getString(TAG_HREF);



            HashMap<String, String> map = new HashMap<String, String>();

         //  map.put(TAG_TIMESTAMP, timestamp);
            map.put(TAG_NAME, name);
           // map.put(TAG_NEWS, news);
           // map.put(TAG_HEADLINES, headlines);
            map.put(TAG_ID, id);
         //   map.put(TAG_HREF, href);
            sportsList.add(map);
         }
    }
        catch (JSONException e) {
            e.printStackTrace();    

        }


    ListAdapter adapter = new SimpleAdapter(this, sportsList,
            R.layout.list_item,
            new String[]{TAG_NAME,TAG_ID} , new int[] {
            R.id.id,R.id.name});

   setListAdapter(adapter);   
 }
}

这里是我的链接我使用

示例链接

Answer 1:

我会建议你使用GSON 。 对我来说，更容易的工作？

编辑：（一些示例代码）

1. 下载GSON-2.2.2.jar它添加到你的依赖

2. 创建一个基类（当你使用一个以上的请求）

    public abstract class RequestBase { public String ToJson(){ Gson gson = new Gson(); return gson.toJson(this); } public abstract String getUrl(); protected String getBaseUrl(){ return //Your URL; } } 

3. 做一个类将执行你的要求..

4. 请为请求和响应类。 然后，你可以用getter和setter方法输入它们：

   公共类SomeRequest扩展RequestBase {@SerializedName（“参数1”）私人诠释参数1;

    public void setParameter1(int Parameter1) { this.Parameter1= Parameter1; } public int getParameter1() { return Parameter1; } @Override public String getUrl() { return this.getBaseUrl() +"YOUR/OWN/URL" + Parameter1; } } 

和

public class SomeResponse {
@SerializedName("responseParameter1")
private int responseParameter1;

@SerializedName("responseParameter2")
private String responseParameter2;

public void setResponseParameter1(int responseParameter1) {
    this.responseParameter1= responseParameter1;
}

public int getResponseParameter1() {
    return responseParameter1;
}

public void setResponseParameter2(String responseParameter2) {
    this.responseParameter2= responseParameter2;
}

public String getResponseParameter1() {
    return responseParameter2;
}
}

文章来源: How to parse Inner json objects arrays