我期待在创建的方式偶然性表在SQL Server 2008中他们并不一定要出现在2×2矩阵的典型。 我只是想知道,如果有人在那里可以看到比我更好的解决方案。
请参考图片的清晰度。 红色的字母是为了简单起见平方的名字。 标签X +是指X是存在于该小区和相反也是如此。
我将我的标签与查询框的字母表,它们代表
A
select count(*) from
(
select distinct p.patientid
from Patient as p
inner join icdpatient as picd on picd.patientid = p.patientid
and picd.admissiondate = p.admissiondate
and picd.dischargedate = p.dischargedate
inner join tblicd as t on t.icd_id = picd.icd_id
where t.icdText like '%x%'
) as t
inner join
(
select distinct p.patientid
from Patient as p
inner join icdpatient as picd on picd.patientid = p.patientid
and picd.admissiondate = p.admissiondate
and picd.dischargedate = p.dischargedate
inner join tblicd as t on t.icd_id = picd.icd_id
where t.icdText like '%y%'
) as s on s.patientid=t.patientid
B
select count(*) from
(
select distinct p.patientid
from Patient as p
inner join icdpatient as picd on picd.patientid = p.patientid
and picd.admissiondate = p.admissiondate
and picd.dischargedate = p.dischargedate
inner join tblicd as t on t.icd_id = picd.icd_id
where t.icdText like '%x%'
) as t
left join
(
select distinct p.patientid
from Patient as p
inner join icdpatient as picd on picd.patientid = p.patientid
and picd.admissiondate = p.admissiondate
and picd.dischargedate = p.dischargedate
inner join tblicd as t on t.icd_id = picd.icd_id
where t.icdText like '%y%'
) as s on s.patientid=t.patientid
where s.patientid is null
C
select * from
(
select distinct p.patientid
from Patient as p
inner join icdpatient as picd on picd.patientid = p.patientid
and picd.admissiondate = p.admissiondate
and picd.dischargedate = p.dischargedate
inner join tblicd as t on t.icd_id = picd.icd_id
where t.icdText like '%x%'
) as t
right join
(
select distinct p.patientid
from Patient as p
inner join icdpatient as picd on picd.patientid = p.patientid
and picd.admissiondate = p.admissiondate
and picd.dischargedate = p.dischargedate
inner join tblicd as t on t.icd_id = picd.icd_id
where t.icdText like '%y%'
) as s on s.patientid=t.patientid
where t.patientid is null
d这一次我有点玄乎约,但我想我会做这样的事
declare @d int
set @d = (select count(distinct p.patientid) from Patient as p) - b -c
其目的是发现整个人口减去那些只用X和ONLY,其中y