如何xsl1.0和2.0族元素?(How to group elements in xsl1.0 a

2019-10-16 17:22发布

这样的例子

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <a id='a1' name='a1 is a Chinese pig'/>
    <b text='b1'/>
    <d test='test0' location='L0' text='c0'/>
    <a id='a2' name='a2 is a Japanese pig'/>
    <b text='b2'/>
    <c test='test1' location='L1' text='c1 is a red pig'/>
    <c test='test2' location='L2' text='c2 is a green pig'/>
    <a id='a3' name='a3 is a American dog'/>
    <b text='b3'/>
    <c test='test3' location='L3' text='c3 is a lovely dog'/>
    <c test='test4' location='L4' text='c4 is a ugly dog'/>
    <c test='test5' location='L5' text='c5 is a smart dog'/>
    <a id='a4' name='a4 is a Japanese bird'/>
    <b text='b4'/>
    <c test='test6' location='L6' text='c6 is a lovely bird'/>
    <c test='test7' location='L7' text='c7 is a ugly bird'/>
    <c test='test8' location='L8' text='c8 is a smart bird'/>   
    <a id='a5' name='a5 is a American pig'/>
    <b text='b2'/>
    <c test='test10' location='L10' text='c10 is a red pig'/>
    <c test='test11' location='L11' text='c11 is a green pig'/>
    <a id='a6' name='a6 is a Chinese dog'/>
    <b text='b3'/>
    <c test='test12' location='L12' text='c12 is a lovely dog'/>
    <c test='test14' location='L14' text='c14 is a ugly dog'/>
    <c test='test15' location='L15' text='c15 is a smart dog'/>
    <a id='a7' name='a7 is a Chinese bird'/>
    <b text='b4'/>
    <c test='test16' location='L16' text='c16 is a lovely bird'/>
    <c test='test17' location='L17' text='c17 is a ugly bird'/>
    <c test='test18' location='L18' text='c18 is a smart bird'/>        
</root>

我申请这样的xsl1.0

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="text" indent="yes"/>

   <xsl:key name="lookup" match="c" use="generate-id(preceding-sibling::a[1])" />
   <xsl:template match="/root">
      <xsl:apply-templates select="a[key('lookup', generate-id())]" />
   </xsl:template>

   <xsl:template match="a">dog:<xsl:value-of select="concat(@name[contains(.,'dog')], ':&#13;', '&#13;')" />
      <xsl:apply-templates select="key('lookup', generate-id())" />
   </xsl:template>

   <xsl:template match="c">
      <xsl:apply-templates select="@*" />
      <xsl:value-of select="'&#13;'" />
   </xsl:template>

   <xsl:template match="c/@*">
      <xsl:value-of select="concat(local-name(), ':', ., ':&#13;')" />
   </xsl:template>
</xsl:stylesheet>

我想这样的输出,该规则是

  1. 如果有一个或多个下面的一个元素与下一一个C之间的元件,那么我们OUPUT使用这些C元件
  2. 然后根据@name,检查值包含一些字符串如猪,狗或鸟,这些都是关键的话,不只是一个硬编码在这里工作。 我们可以组这些信息,因为有更多的猪,鸟类和dogs.not不管他们是中国人还是日本人,否则,我们根据狗,鸟,猪这些类别中,我们知道之前组。

我想输出是这样的

case1:the following are  all pigs:

a2 is a Japanese pig

test:test1
location:L1
text:c1 is a red pig
test:test2
location:L2
text:c2 is a green pig

a5 is a American pig

test:test10
location:L10
text:c10 is a red pig
test:test11
location:L11
text:c11 is a green pig

case2:the following are  all dogs:

a3 is a American dog

test:test3
location:L3
text:c3 is a lovely dog

test:test4
location:L4
text:c4 is a ugly dog

test:test5
location:L5
text:c5 is a smart dog

a6 is a Chinese dog

test:test12
location:L12
text:c12 is a lovely dog

test:test14
location:L14
text:c14 is a ugly dog

test:test15
location:L15
text:c15 is a smart dog    

case3:the following are  all birds:

a4 is a Japanese bird
test:test6
location:L6
text:c6 is a lovely bird

test:test7
location:L7
text:c7 is a ugly bird

test:test8
location:L8
text:c8 is a smart bird

a7 is a Chinese bird

test:test16
location:L16
text:c16 is a lovely bird

test:test17
location:L17
text:c17 is a ugly bird

test:test18
location:L18
text:c18 is a smart bird   

现在的问题是如何纠正我的xsl1.0? 还有一个就是这更容易xsl2.0实现?

Answer 1:

与此XSL

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="text" indent="yes"/>
   <xsl:template match="/root">
      <p>the followings are birds:</p>
      <xsl:apply-templates select="a[contains(@name, 'bird')][key('bird_lookup', generate-id())]"/>
      <p>the followings are pigs:</p>
      <xsl:apply-templates select="a[contains(@name, 'pig')][key('pig_lookup', generate-id())]"/> 
      <p>the followings are dogs:</p>
      <xsl:apply-templates select="a[contains(@name, 'dog')][key('dog_lookup', generate-id())]"/>                
   </xsl:template>
   <xsl:key name="bird_lookup" match="c" use="generate-id(preceding-sibling::a[1][contains(@name, 'bird')])"/>
   <xsl:template name="bird" match="a[contains(@name, 'bird')]">
      <xsl:value-of select="'&#13;'"/> 
      <xsl:value-of select="@name"/>
      <xsl:value-of select="'&#13;'"/>      
      <xsl:apply-templates select="key('bird_lookup', generate-id())" />
      <xsl:apply-templates select="c/@*"/>
   </xsl:template>

   <xsl:key name="pig_lookup" match="c" use="generate-id(preceding-sibling::a[1][contains(@name, 'pig')])"/>
   <xsl:template name="pig" match="a[contains(@name, 'pig')]">
         <xsl:value-of select="'&#13;'"/> 
      <xsl:value-of select="@name"/>
      <xsl:value-of select="'&#13;'"/>      
      <xsl:apply-templates select="key('pig_lookup', generate-id())" />
      <xsl:apply-templates select="c/@*"/>
   </xsl:template>

      <xsl:key name="dog_lookup" match="c" use="generate-id(preceding-sibling::a[1][contains(@name, 'dog')])"/>
   <xsl:template name="dog" match="a[contains(@name, 'dog')]">
      <xsl:value-of select="'&#13;'"/>     
      <xsl:value-of select="@name"/>
      <xsl:value-of select="'&#13;'"/>      
      <xsl:apply-templates select="key('dog_lookup', generate-id())" />
      <xsl:apply-templates select="c/@*"/>
   </xsl:template>


   <xsl:template match="c">
      <xsl:apply-templates select="@*"/>
      <xsl:value-of select="'&#13;'"/>
   </xsl:template>

   <xsl:template match="c/@*">
      <xsl:value-of select="concat(local-name(), ':', ., '&#13;')"/>
   </xsl:template>

</xsl:stylesheet>

我可以得到

the followings are birds:
a4 is a Japanese bird
test:test6
location:L6
text:c6 is a lovely bird

test:test7
location:L7
text:c7 is a ugly bird

test:test8
location:L8
text:c8 is a smart bird


a7 is a Chinese bird
test:test16
location:L16
text:c16 is a lovely bird

test:test17
location:L17
text:c17 is a ugly bird

test:test18
location:L18
text:c18 is a smart bird

the followings are pigs:
a2 is a Japanese pig
test:test1
location:L1
text:c1 is a red pig

test:test2
location:L2
text:c2 is a green pig


a5 is a American pig
test:test10
location:L10
text:c10 is a red pig

test:test11
location:L11
text:c11 is a green pig

the followings are dogs:
a3 is a American dog
test:test3
location:L3
text:c3 is a lovely dog

test:test4
location:L4
text:c4 is a ugly dog

test:test5
location:L5
text:c5 is a smart dog


a6 is a Chinese dog
test:test12
location:L12
text:c12 is a lovely dog

test:test14
location:L14
text:c14 is a ugly dog

test:test15
location:L15
text:c15 is a smart dog

如何让这个优雅?



文章来源: How to group elements in xsl1.0 and 2.0?
标签: xslt