我有一个网站，我需要得到一个网页的URL与PHP。 网址可能是东西www.mydomain.com/thestringineed/ ，也可以www.mydomain.com/thestringineed?data=1或可以www.mydomain.com/ss/thestringineed
所以它总是最后一个字符串，但我不想以后得到什么？
Answer 1:
您将使用parse_url功能，再看看返回的路径部分。 像这样：
$url='www.mydomain.com/thestringineed?data=1';
$components=parse_url($url);
//$mystring= end(explode('/',$components['path']));
// I realized after this answer had sat here for about 3 years that there was
//a mistake in the above line
// It would only give the last directory, so if there were extra directories in the path, it would fail. Here's the solution:
$mystring=str_replace( reset(explode('/',$components['path'])),'',$components['path']); //This is to remove the domain from the beginning of the path.
// In my testing, I found that if the scheme (http://, https://, ...) is present, the path does not include
//the domain. (it's available on it's own as ['host']) In that case it's just
// $mystring=$components['path']);
Answer 2:
parse_url应该帮助你。
<?php
$url = "http://www.mydomain.com/thestringineed/";
$parts = parse_url($url);
print_r($parts);
?>
Answer 3:
parse_url()是您正在寻找的功能。 你想确切的部分，可以通过接收PHP_URL_PATH
$url = 'http://php.net/manual/en/function.parse-url.php';
echo parse_url($url, PHP_URL_PATH);
Answer 4:
使用$_SERVER['REQUEST_URI']会返回完整当前页面的URL，你可以用“/”分开，并利用最后的数组索引。 这将是最后一个字符串
Answer 5:
您可以使用：
$strings = explode("/", $urlstring);
这将删除所有的“/”在url并返回包含的所有单词的数组。
$strings[count($strings)-1]
现在有你需要的字符串值，但它可能包含，所以我们需要删除“数据= 1？”：
$strings2 = explode("?", $strings[count($strings)-1]);
$strings2[0]
有你是想出来的URL字符串。
希望这可以帮助！
Answer 6:
<?php
$url = 'http://username:password@hostname/path?arg=value#anchor';
print_r(parse_url($url));
echo parse_url($url, PHP_URL_PATH);
?>
和你出来卖出期权
Array
(
[scheme] => http
[host] => hostname
[user] => username
[pass] => password
[path] => /path
[query] => arg=value
[fragment] => anchor
)
/path
文章来源: Get part of URL with PHP
