问题:

I have a table with the following columns in a Netezza Database

Id  field1  field2      
 1   0.9    sum(field1)/0.9
 2   1.7    sum(field1)/1.7
 3   6.9    sum(field1)/6.9
 4   0.4    sum(field1)/0.4
 5   0.2    sum(field1)/0.2
 6   2.8    sum(field1)/2.8
 7   7.0    sum(field1)/7.0

The field2 column is to be generated and will hold values as shown in the table.

For this example the sum of field1 is 19.9.

Also the field1 values will change frequently.

Please help with a query that will help calculate the field2 value also the values are in decimals so will want the precise sum.

Thanks

回答1:

You can use SUM with the OVER Clause .

select Id,
       field1,
       (sum(field1) over() / field1) as field2
from YourTable

SQLFiddle

回答2:

You can use OUTER APPLY:

select t1.id,
  t1.field1,
  (t2.field1 / t1.field1) field2
from table1 t1
outer apply
(
  select sum(field1) field1
  from table1
) t2

see SQL Fiddle with Demo

If you don't have access to outer apply then you can use a cartesian result query:

select t1.id,
  t1.field1,
  (t2.field1 / t1.field1) field2
from table1 t1, 
(
  select sum(field1) field1
  from table1
) t2

See SQL Fiddle with Demo

回答3:

SELECT  a.*, (b.totalSum / a.field1)
FROM    table1 a
        CROSS JOIN
        (
            SELECT SUM(filed1) totalSum
            FROM tableName
        ) b