添加连接结果基于从连接值新列(Add join results as new column base

2019-09-30 05:35发布

我从来没有做过这样的事情,我试图找到它在谷歌,但没有结果。

我有3个表看起来像这样:

命令:

OdredID (int) PK,
UserID (int) FK,
OdredDate (datetime)

组件:

ComponentID (int) PK,
Name (nvarchar(50)),
Type (nvarchar(max))

订购组件:

OrderComponentID (int) PK,
OrderID (int) FK,
ComponentID (int) FK,
Value (nvarchar(max))

可以说,一个为了有3个部件具有名称: [CPU, Motherboard, Memory]和值[1GHz, AsusP5, 2GB Kingston DDR3]

我需要一个结果具有这样的列:

OrderID  UserID   Date          CPU    Motherboard   Memory
   1        1     2012-05-21    1GHz   AsusP5        2GB Kingston DDR3

基本上,我需要每加入一行取自名字去为新列Name从连接表和值的列Value列。

Answer 1:

尝试这个:

SELECT
  o.orderid,
  o.userid,
  MAX(CASE WHEN c.Name = 'CPU' THEN oc.Value END) AS 'CPU',
  MAX(CASE WHEN c.Name = 'Motherboard' THEN oc.Value END) AS 'Motherboard',
  MAX(CASE WHEN c.Name = 'Memory' THEN oc.Value END) AS 'Memory'
FROM orders o
INNER JOIN ordercomponents oc ON c.orderid = oc.orderId
INNER JOIN Components c ON oc.componentid = c.componentid
GROUP BY o.orderid, o.userid

SQL小提琴演示

需要注意的是:该标准SQL的方式来做到这一点。 但是你可以使用SQL Server PIVOT表运营商做同样的事情,像这样:

SELECT  *
FROM
(
   SELECT o.orderid, o.userid, c.Name 'Name', oc.value 'value'
   FROM orders o
   INNER JOIN ordercomponent oc ON o.orderid = oc.orderId
   INNER JOIN Components c ON oc.componentid = c.componentid
 ) t 
PIVOT
(
  MAX(value)
  FOR Name IN ([CPU], [Motherboard], [Memory])
) p;

但是,这对于一组预先定义的值等[CPU], [Motherboard], [Memory]

对于未知数量的值,你必须动态地做到这一点,如下所示:

DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);

select @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.name) 
                    from Components c
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT orderid, userid  ' + @cols + ' from 
             (
                 select o.orderid, o.userid, c.Name Name, oc.value value
                 FROM orders o
                 INNER JOIN ordercomponent oc ON o.orderid = oc.orderId
                 INNER JOIN Components c ON oc.componentid = c.componentid
            ) x
            pivot 
            (
                max(value)
                for name in (' + @cols + ')
            ) p '

execute(@query);

更新SQL小提琴演示



文章来源: Add join results as new column based on values from join