我编码一个计划,将需要的功能改变标签和文本输入到文本框,但是我不知道如何与节目的新风格,我使用(面向对象),它这么做。 我已经做了,但是我生成使用此代码的帧之前的程序:
f = [Frame(root) for i in range(0,5)]
for i in f:
i.place(relx=0,rely=0,relwidth=1,relheight=1)
然后我把它们都放在一个类但是我跑了很糟糕的形式,所以我重做。 到目前为止我的代码如下:
import tkinter as tk
import datetime,time,os,sys
import sqlite3 as lite
from datetime import date
Title_Font= ("Times", 18, "underline italic")
unix = time.time()
time_curr = str(datetime.datetime.fromtimestamp(unix).strftime('%H:%M'))
date1 = str(datetime.datetime.fromtimestamp(unix).strftime('%d-%m-%Y'))
class Creating_Stuff(tk.Tk):
def __init__(self, *args, **kwargs):
tk.Tk.__init__(self, *args, **kwargs)
container = tk.Frame(self)
container.pack(side="top", fill="both", expand = True)
container.grid_rowconfigure(0, weight=1)
container.grid_columnconfigure(0, weight=1)
self.frames = {}
for F in (StartPage, PageOne, PageTwo):
frame = F(container, self)
self.frames[F] = frame
frame.grid(row=0, column=0, sticky="nsew")
self.show_frame(StartPage)
def show_frame(self, cont):
frame = self.frames[cont]
frame.tkraise()
class StartPage(tk.Frame):
def __init__(self, parent, controller):
tk.Frame.__init__(self,parent)
self.grid_columnconfigure(0, weight=1)
self.grid_columnconfigure(3, weight=1)
self.option_add( "*font", "Times 12" )
self.tk_setPalette(background='#bbfff0', foreground='black',
activeBackground='#d9d9d9', activeForeground='#ff9933')
label = tk.Label(self, text="Laptop Booking System", font=Title_Font)
label.grid(row=0, column=1, pady = 30)
time = tk.Label(self, text="Time: " + time_curr + "\nDate: " + date1, font="Times 10")
time.grid(row=0, column=2,columnspan=2)
Booking_1 = tk.Button(self, text="Booking",
command=lambda: controller.show_frame(PageOne),bg='#f2f2f2',width=20)
Booking_1.grid(row=2, column=1, pady=10)
Tbl_q1 = tk.Button(self, text="Table Querying",
command=lambda: controller.show_frame(PageTwo),bg='#f2f2f2',width=20)
Tbl_q1.grid(row=3, column=1, pady=10)
Exit = tk.Button(self, text ="Exit",command=lambda:destroy(),bg='#f2f2f2')
Exit.grid(row=5, column=1)
class PageOne(tk.Frame):
def __init__(self, parent, controller):
tk.Frame.__init__(self, parent)
self.grid_columnconfigure(0, weight=1)
self.grid_columnconfigure(3, weight=1)
label = tk.Label(self, text="Page One!!!", font=Title_Font)
label.grid(row=1, column=1)
bk2_menu = tk.Button(self, text="Back to Home",
command=lambda: controller.show_frame(StartPage))
bk2_menu.grid(row=3, column=1)
class PageTwo(tk.Frame):
def __init__(self, parent, controller):
tk.Frame.__init__(self, parent)
self.grid_columnconfigure(0, weight=1)
self.grid_columnconfigure(3, weight=1)
label = tk.Label(self, text="Page Two!!!", font=Title_Font)
label.grid(row=1, column=1)
bk2_Menu2 = tk.Button(self, text="Back to menu",
command=lambda: controller.show_frame(StartPage))
bk2_Menu2.grid(row=3, column=1)
app = Creating_Stuff()
def destroy():
app.destroy()
app.title("Laptop Booking System")
app.geometry("700x400")
app.mainloop()
如果你尝试一下它的工作原理但是它只是有3级不同的帧。 我怎样才能在一个帧获得按钮以使标签说“你好”的框架被压后?