[removed] why “this” inside the private function r

Consider the following code:

function A() {}    

A.prototype.go = function() {
    console.log(this); //A { go=function()}

    var f = function() {
         console.log(this);  //Window              
    };

    f();
}

var a = new A();
a.go();

Why does 'this' inside function 'f' refers to the global scope? Why it is not the scope of function 'A' ?

回答1:

JavaScript has a different concept of what the special name this refers to than most other programming languages do. There are exactly five different ways in which the value of this can be bound in the language.

The Global Scope

this;

When using this in global scope, it will simply refer to the global object.

Calling a Function

foo();

Here, this will again refer to the global object.

ES5 Note: In strict mode, the global case no longer exists. this will instead have the value of undefined in that case.

Calling a Method

test.foo();

In this example, this will refer to test.

Calling a Constructor

new foo();

A function call that is preceded by the new keyword acts as a constructor. Inside the function, this will refer to a newly created Object.

Explicit Setting of `this`

function foo(a, b, c) {}

var bar = {};
foo.apply(bar, [1, 2, 3]); // array will expand to the below
foo.call(bar, 1, 2, 3); // results in a = 1, b = 2, c = 3

When using the call or apply methods of Function.prototype, the value of this inside the called function gets explicitly set to the first argument of the corresponding function call.

As a result, in the above example the method case does not apply, and this inside of foo will be set to bar.

Note: this cannot be used to refer to the object inside of an Object literal. So var obj = {me: this} will not result in me referring to obj, since this only gets bound by one of the five listed cases.

Common Pitfalls

While most of these cases make sense, the first one is to be considered another mis-design of the language because it never has any practical use.

Foo.method = function() {
    function test() {
        // this is set to the global object
    }
    test();
}

A common misconception is that this inside of test refers to Foo; while in fact, it does not.

In order to gain access to Foo from within test, it is necessary to create a local variable inside of method which refers to Foo.

Foo.method = function() {
    var that = this;
    function test() {
        // Use that instead of this here
    }
    test();
}

that is just a normal variable name, but it is commonly used for the reference to an outer this. In combination with closures, it can also be used to pass this values around.

Assigning Methods

Another thing that does not work in JavaScript is function aliasing, which is assigning a method to a variable.

var test = someObject.methodTest;
test();

Due to the first case, test now acts like a plain function call; therefore, this inside it will no longer refer to someObject.

While the late binding of this might seem like a bad idea at first, in fact, it is what makes prototypal inheritance work.

function Foo() {}
Foo.prototype.method = function() {};

function Bar() {}
Bar.prototype = Foo.prototype;

new Bar().method();

When method gets called on a instance of Bar, this will now refer to that very instance.

Disclaimer: Shamelessy stolen from my own resources at http://bonsaiden.github.com/JavaScript-Garden/#function.this

回答2:

The reason why is you are invoking f as a function and not a method. When invoked as a function this is set to window during the execution of the target

// Method invocation.  Invoking a member (go) of an object (a).  Hence 
// inside "go" this === a
a.go();

// Function invocation. Invoking a function directly and not as a member
// of an object.  Hence inside "f" this === window
f(); 

// Function invocation. 
var example = a.go;
example();

回答3:

The scope of all functions is window.

To circumvent that, you can do this:

function A() {}    

A.prototype.go = function() {
    var self = this;
    console.log(self); //A { go=function()}
    var f = function() {
         console.log(self);  //A { go=function()}           
    };

    f();
}

回答4:

Because function f() is not called without any object reference. Try,

f.apply(this);