表示matlab在X相似值和y轴(showing similar value in x and y-

我有如下矩阵; 从计算会有一些值，该值将是具有相同的值彼此当图表描绘（我用散点图），这里的问题是如何知道/识别计算正在给匹配数据，并可以将其存储在表中。我曾尝试使用查找功能的MATLAB中，但出现错误。

A = [2/3 -1/3 -1/3;
    -1/3 2/3 -1/3;
    -1/3 -1/3 2/3];
B=[0 0 0;
    0 0 1;
    0 1 0;
    0 1 1;
    1 0 0;
    1 0 1;
    1 1 0;
    1 1 1];
d= [2/3 -1/3 -1/3];
q = [0 0.5773 -0.5773];
for i = 1:size(B,1)
    p1 =  A * B(1,:)' -A * B(i,:)';
    dtransformation0a(i) = d*p1;
    qtransformation0a(i) = q*p1;
    p2 =  A * B(2,:)' -A * B(i,:)'
    dtransformation0b(i) = d*p2;
    qtransformation0b(i) = q*p2;
     p3 =  A * B(3,:)' -A * B(i,:)';
    dtransformation0c(i) = d*p3;
    qtransformation0c(i) = q*p3;
    p4 =  A * B(4,:)' -A * B(i,:)';
    dtransformation0d(i) = d*p4;
    qtransformation0d(i) = q*p4;
    p5 =  A * B(5,:)' -A * B(i,:)';
    dtransformation0e(i) = d*p5;
    qtransformation0e(i) = q*p5;
    p6 =  A * B(6,:)' -A * B(i,:)';
    dtransformation0f(i) = d*p6;
    qtransformation0f(i) = q*p6;
end
figure
 scatter(dtransformation0a,qtransformation0a,100,'b.')
hold on
scatter(dtransformation0b,qtransformation0b,100,'b.')
hold on

我没有访问MATLAB解释所以我现在不能测试它自己，但这应该工作：

A = [2/3 -1/3 -1/3;
    -1/3 2/3 -1/3;
    -1/3 -1/3 2/3];
B = [0 0 0;
    0 0 1;
    0 1 0;
    0 1 1;
    1 0 0;
    1 0 1;
    1 1 0;
    1 1 1];
d = [2/3 -1/3 -1/3];
q = [0 0.5773 -0.5773];
for i = 1:size(B,1)
    p1 =  A * B(1,:)' -A * B(i,:)';
    dtransformation0a(i) = d*p1;
    qtransformation0a(i) = q*p1;
    p2 =  A * B(2,:)' -A * B(i,:)'
    dtransformation0b(i) = d*p2;
    qtransformation0b(i) = q*p2;
     p3 =  A * B(3,:)' -A * B(i,:)';
    dtransformation0c(i) = d*p3;
    qtransformation0c(i) = q*p3;
    p4 =  A * B(4,:)' -A * B(i,:)';
    dtransformation0d(i) = d*p4;
    qtransformation0d(i) = q*p4;
    p5 =  A * B(5,:)' -A * B(i,:)';
    dtransformation0e(i) = d*p5;
    qtransformation0e(i) = q*p5;
    p6 =  A * B(6,:)' -A * B(i,:)';
    dtransformation0f(i) = d*p6;
    qtransformation0f(i) = q*p6;
end

X = [dtransformation0a, dtransformation0b];    %Assuming dtransformation0a and dtransformation0b are row martices.
Y = [qtransformation0a, qtransformation0b];    %Assuming qtransformation0a and qtransformation0b are row martices.
my_points = [X';Y'];    %Each row of my_points will represent a particular point.
my_points = unique(my_points, 'rows');    %Get unique rows, hence points.

figure
scatter(my_points(:,1),my_points(:,2),100,'b.')

让我知道，如果你面对任何问题。

编辑！！

按您的要求说，我的理解是，你想显示那些产生价值，比如说计算， (0,0) ; 如果这确实是你想要的，你应该能够通过更换循环部分得到它：

my_point = [0, 0];
for i = 1:size(B,1)
    p1 =  A * B(1,:)' -A * B(i,:)';
    dtransformation0a(i) = d*p1;
    qtransformation0a(i) = q*p1;
    p2 =  A * B(2,:)' -A * B(i,:)'
    dtransformation0b(i) = d*p2;
    qtransformation0b(i) = q*p2;
     p3 =  A * B(3,:)' -A * B(i,:)';
    dtransformation0c(i) = d*p3;
    qtransformation0c(i) = q*p3;
    p4 =  A * B(4,:)' -A * B(i,:)';
    dtransformation0d(i) = d*p4;
    qtransformation0d(i) = q*p4;
    p5 =  A * B(5,:)' -A * B(i,:)';
    dtransformation0e(i) = d*p5;
    qtransformation0e(i) = q*p5;
    p6 =  A * B(6,:)' -A * B(i,:)';
    dtransformation0f(i) = d*p6;
    qtransformation0f(i) = q*p6;

    if(dtransformation0a(i)==my_point(1))
        fprintf("dtransformation0a => (%f = %f * %f;)\n",dtransformation0a(i),d,p1);
    end
    if(dtransformation0b(i)==my_point(1))
        fprintf("dtransformation0b => (%f = %f * %f;)\n",dtransformation0b(i),d,p2);
    end
    if(qtransformation0a(i)==my_point(2))
        fprintf("qtransformation0a => (%f = %f * %f;)\n",qtransformation0a(i),q,p1);
    end
    if(qtransformation0b(i)==my_point(2))
        fprintf("qtransformation0b => (%f = %f * %f;)\n",qtransformation0b(i),q,p2);
    end
end

我希望这是你在找什么。