下面的方法，当与像称为String val = getCell("SELECT col FROM table WHERE LIKE(other_col,'?')", new String[]{"value"}); （这是SQLite的），将引发java.lang.ArrayIndexOutOfBoundsException: 0 at org.sqlite.PrepStmt.batch(PrepStmt.java:131) 任何人都可以承担我那可怜的装模作样可惜这里帮我，为什么 ？
/**
* Get a string representation of the first cell of the first row returned
* by <code>sql</code>.
*
* @param sql The SQL SELECT query, that may contain one or more '?'
* IN parameter placeholders.
* @param parameters A String array of parameters to insert into the SQL.
* @return The value of the cell, or <code>null</code> if there
* was no result (or the result was <code>null</code>).
*/
public String getCell(String sql, String[] parameters) {
String out = null;
try {
PreparedStatement ps = connection.prepareStatement(sql);
for (int i = 1; i <= parameters.length; i++) {
String parameter = parameters[i - 1];
ps.setString(i, parameter);
}
ResultSet rs = ps.executeQuery();
rs.first();
out = rs.getString(1);
rs.close();
ps.close();
} catch (SQLException e) {
e.printStackTrace();
}
return out;
}
该setString()会，在这种情况下，是ps.setString(1, "value")不应该是一个问题。 显然我错了，虽然。
提前谢谢了。
