下面是从(东西类似)我的模型摘录:
class Person(models.Model):
name = models.CharField(max_length=20)
relationships = models.ManyToManyField('self',
through='Relationship',
symmetrical=False,
related_name='related_to',
)
def __str__(self):
return self.name
class Relationship(models.Model):
from_person = models.ForeignKey(Person,
related_name='from_people',
on_delete=models.CASCADE,
)
to_person = models.ForeignKey(Person,
related_name='to_people',
on_delete=models.CASCADE,
)
status = models.CharField(max_length=20)
def __str__(self):
return "{} is {} {}".format(
self.from_person.name, self.status, self.to_person.name)
这里是我的数据库中的内容:
>>> Person.objects.all()
<QuerySet [<Person: A>, <Person: B>, <Person: C>]>
>>> Relationship.objects.all()
<QuerySet [<Relationship: B is Following C>]>
如果我想看到一个特定的人是继谁,我可以建立一个新的方法引入Person类:
def get_following(self):
return self.relationships.filter(
to_people__status='Following',
to_people__from_person=self)
这工作:
>>> p2.get_following()
<QuerySet [<Person: C>]>
我想要做的这个相反。 不要问“谁这个人跟着我来?”,我想问“谁遵循这个人吗?”。 我是这样做的(虽然它返回的关系对象,而不是Person对象):
>>> Relationship.objects.filter(to_person=p3, status='Following')
<QuerySet [<Relationship: B is Following to C>]>
我尝试的(这将返回一个空查询集):
def get_following(self):
return self.relationships.filter(
from_people__status='Following',
from_people__to_person=self)
您的帮助表示赞赏!
编辑:这是我选择的答案:
def get_followers(self):
return self.related_to.filter(from_people__status='Following')
万一别人需要完全像你描述的实施“追随者”的另一种方式,但有不同的造型方案:
# project/account/models.py
from django.db import models
from django.contrib.auth.models import AbstractBaseUser, BaseUserManager, PermissionsMixin
from model_utils import Choices
class User(AbstractBaseUser, PermissionsMixin):
class Meta:
# ...
username = models.CharField(...)
email = models.EmailField(...)
# ...
### Custom app-specific relationships (database scheme) ###
# symmetrical=False is needed for this reason: https://stackoverflow.com/a/42040848/3433137
following = models.ManyToManyField('self', related_name='followers', blank=True, symmetrical=False)
# project/account/forms.py
from django import forms
from django.contrib.auth import get_user_model
from django.contrib.admin.widgets import FilteredSelectMultiple
from .models import User
class UserChangeForm(forms.ModelForm):
# ...
# new:
following = forms.ModelMultipleChoiceField(
queryset=User.objects.all(),
required=False,
widget=FilteredSelectMultiple(
verbose_name='Following',
is_stacked=False
)
)
# new:
followers = forms.ModelMultipleChoiceField(
queryset=User.objects.all(),
required=False,
widget=FilteredSelectMultiple(
verbose_name='Followers',
is_stacked=False
)
)
class Meta:
model = get_user_model()
# add 'following' and 'followers' to the fields:
fields = ('email', 'password', ..., 'following', 'followers')
# also needed to initialize properly:
def __init__(self, *args, **kwargs):
super(UserChangeForm, self).__init__(*args, **kwargs)
# Filter out the self user in the lists and initialize followers list:
if self.instance and self.instance.pk:
self.fields['following'] = forms.ModelMultipleChoiceField(
queryset=User.objects.all().exclude(pk=self.instance.pk),
required=False,
widget=FilteredSelectMultiple(
verbose_name='Following',
is_stacked=False
)
)
self.fields['followers'] = forms.ModelMultipleChoiceField(
queryset=User.objects.all().exclude(pk=self.instance.pk),
required=False,
widget=FilteredSelectMultiple(
verbose_name='Followers',
is_stacked=False
)
)
self.fields['followers'].initial = self.instance.followers.all()
# project/account/admin.py
from django.contrib.auth import get_user_model
from django.contrib import admin
from django.contrib.auth.models import Group
from django.contrib.auth.admin import UserAdmin as BaseUserAdmin
from .models import User
from .forms import UserChangeForm, UserCreationForm
class Admin(BaseUserAdmin):
add_form = UserCreationForm
form = UserChangeForm
model = get_user_model()
# The fields to be used in displaying the User model.
# These override the definitions on the base UserAdmin
# that reference specific fields on auth.User.
list_display = ['email', 'username', 'is_admin']
list_filter = ('is_admin',)
fieldsets = (
(None, {'fields': ('email', 'password')}),
('Personal info', {'fields': ('username',)}),
('Permissions', {'fields': ('is_admin', 'is_superuser', 'is_staff')}),
# new:
('Following / Followers', {'fields': ('following', 'followers')}),
)
# other fields
# ...
# new:
filter_horizontal = ('following', 'followers')
admin.site.register(User, Admin)
admin.site.unregister(Group)
如果然后启动服务器,去为localhost:8000 /管理/并导航到用户的详细页面,你会看到这样的事情在屏幕上:
所以你能看到追随者量一次在list_view我没加计数器。
需要注意的是与追随者第二FormField是只读的管理面板。 用户不能选择其他用户跟随他。
你有一个查询集是这样的: <QuerySet [<Relationship: B is Following C>]>
想有一天(我猜想,这是建议的)“人”有大量的追随者,它可能会返回这么多的追随者,像这样的: <QuerySet [<Relationship: B is Following C>, <Relationship: A is Following C>]>
。 所以,我会用values_list()[1]:
Relationship.objects.filter(to_person=p3, status='Following').values_list('from_person__name', flat=True)
返回: <QuerySet [A, B, ...]>
如果你只有在一个单场传球,你也可以通过在平坦的参数。 如果属实,这将意味着返回的结果是单值,而不是一个元组。
或创建一个方法:
def get_followers(self):
follower_of_person = []
for value in relation_of_person:
follower_of_p3.append(value.from_person.name)
return follower_of_person
返回: [A, B, ...]
values_list仍然是更好的,因为你是在数据库中直接工作。
[1] https://docs.djangoproject.com/en/2.0/ref/models/querysets/#values-list (这里有多对多的一个很好的例子)。
看看这个文件。 否则,这里有一些其他的方法?
self.relationships.from_people.objects.all()
将与返回所有对象与相关名称from_people
。
我会,不过,稍微改变了一些代码,这样使用会self.relationships.from_people.objects.filter(status='Following')
另一种方式来做到这一点(虽然不是最有效的),是在人的模型来传递,并且使用person.pk作为过滤器中的关系模型通过。
def get_following(self, pk):
person = Person.objects.get(pk=pk)
relationships = Relationship.objects.filter(to_person=person.id)
return relationships
这是我选择的答案:
def get_followers(self):
return self.related_to.filter(from_people__status='Following')