为什么当两个自定义控件增加了定时器设计师放缓？(Why does the designer slow

我有一个长期使用过程中的自定义控件。这种控制已经旋转点周围的圈子。要做到这一点，我使用的计时器，正在设计时间和运行时间。当添加一个控制，使得形成是没有问题的。但是他们两个相加形成，设计师减慢这么多。为什么会出现这个问题，怎么解决呢？

从这个项目我的代码：

 public class SpinningCircles : Control
{
    bool fullTransparency = true;
    int increment = 1;
    int radius = 4;
    int n = 8;
    int next = 0;
    int k = 0;
    Timer timer;
    public SpinningCircles()
    {
        timer = new Timer();
        timer.Tick += timer_Tick;
        timer.Enabled = true;
        SetStyle(ControlStyles.AllPaintingInWmPaint | ControlStyles.OptimizedDoubleBuffer | ControlStyles.ResizeRedraw | ControlStyles.UserPaint | ControlStyles.SupportsTransparentBackColor, true);
        BackColor = Color.Transparent;
    }
    void timer_Tick(object sender, EventArgs e)
    {
        Invalidate();
    }
    protected override void OnPaint(PaintEventArgs e)
    {
        if (fullTransparency)
        {
            Transparencer.MakeTransparent(this, e.Graphics);
        }
        e.Graphics.SmoothingMode = SmoothingMode.HighQuality;
        int length = Math.Min(Width, Height);
        PointF center = new PointF(length / 2, length / 2);
        int bigRadius = length / 2 - radius - (n - 1) * increment;
        float unitAngle = 360 / n;
        next++;
        next = next >= n ? 0 : next;
        int a = 0;
        for (int i = next; i < next + n; i++)
        {
            int factor = i % n;
            float c1X = center.X + (float)(bigRadius * Math.Cos(unitAngle * factor * Math.PI / 180));
            float c1Y = center.Y + (float)(bigRadius * Math.Sin(unitAngle * factor * Math.PI / 180));
            int currRad = radius + a * increment;
            PointF c1 = new PointF(c1X - currRad, c1Y - currRad);
            e.Graphics.FillEllipse(Brushes.Black, c1.X, c1.Y, 2 * currRad, 2 * currRad);
            using (Pen pen = new Pen(Color.White, 2))
                e.Graphics.DrawEllipse(pen, c1.X, c1.Y, 2 * currRad, 2 * currRad);
            a++;
        }
    }
    protected override void OnVisibleChanged(EventArgs e)
    {
        timer.Enabled = Visible;
        base.OnVisibleChanged(e);
    }
    public bool FullTransparent
    {
        get
        {
            return fullTransparency;
        }
        set
        {
            fullTransparency = value;
        }
    }
}
public class Transparencer
{
    public static void MakeTransparent(Control cont, Graphics g)
    {
        if (cont.Parent != null)
        {
            Bitmap behind = new Bitmap(cont.Parent.Width, cont.Parent.Height);
            foreach (Control c in cont.Parent.Controls)
                if (c.Bounds.IntersectsWith(c.Bounds) & c != cont)
                    c.DrawToBitmap(behind, c.Bounds);
            g.DrawImage(behind, -cont.Left, -cont.Top);
            behind.Dispose();
        }
    }
}

为什么会出现这个问题，怎么解决呢？

这个问题有什么共同点与设计时间和计时器，但不正确的执行你的MakeTransparent方法。

首先，是在条件的明显的bug

c.Bounds.IntersectsWith(c.Bounds)

这个bug的影响是它要求c.DrawToBitmap比主叫其他每个控制。但DrawToBitmap触发OnPaint ，所以当其他控制也是SpinningCircles ，但它确实是相同的，所以能满足当前调用和你结束了一个无限OnPaint周期。

与预期的固定条件

c.Bounds.IntersectsWith(cont.Bounds)

将尽快在两个自定义控件不重叠解决问题。

整个执行不正确。你不应该在第一个地方做它，但一旦你做到了，它至少应该打电话DrawToBitmap只为与呼叫者相交，并具有较低的ZORDER控制。事情是这样的：

public static void MakeTransparent(Control control, Graphics g)
{
    var parent = control.Parent;
    if (parent == null) return;
    var bounds = control.Bounds;
    var siblings = parent.Controls;
    int index = siblings.IndexOf(control);
    Bitmap behind = null;
    for (int i = siblings.Count - 1; i > index; i--)
    {
        var c = siblings[i];
        if (!c.Bounds.IntersectsWith(bounds)) continue;
        if (behind == null)
            behind = new Bitmap(control.Parent.ClientSize.Width, control.Parent.ClientSize.Height);
        c.DrawToBitmap(behind, c.Bounds);
    }
    if (behind == null) return;
    g.DrawImage(behind, control.ClientRectangle, bounds, GraphicsUnit.Pixel);
    behind.Dispose();
}