SQL算术溢出的标识插入(SQL Arithmetic Overflow for Identity

2019-09-26 15:05发布

我有算术溢出值插入一个查找表的行-ID设置为TINYINT数据类型的错误。 这是不是其中的唯一记录数超过255个值的情况。 这是一个有点不同寻常,在此设置的第一次测试没有出现。

下面的代码的量产版却只有66个独特的价值观,但它是可能的新值可以添加(缓慢,非常小的数字),随着时间的推移... 255个可用插槽应该是绰绰有余的这个寿命分析过程。

我最初的想法是,它可能是由于缓存计划承认分层源表中有超过255个值(有其实1028),和评估,这可能超过目标表的容量。 我已经测试然而,这是不正确的。

-- This table represents a small (tinyint) subset of unique primary values.
CREATE TABLE #tmp_ID10T_Test (
ID10T_Test_ID tinyint identity (1,1) not null,
ID10T_String varchar(255) not null
PRIMARY KEY CLUSTERED
(ID10T_String ASC)
WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = ON, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON)
) ON [PRIMARY]



-- This table represents a larger (smallint) set of non-unique source values, defined by a secondary key value (Value_Set).
CREATE TABLE #tmp_ID10T_Values (
ID10T_Value_ID smallint identity (1,1) not null,
ID10T_Value_Set tinyint not null,
ID10T_String varchar(255) not null
) ON [PRIMARY]



-- Create the initial dataset - 100 unique records; The insertion tests below illustrate that the INDEX is working
--  correctly on the primary key field for repetative values, however something is happening with the IDENTITY field...
DECLARE @ID10T tinyint
, @i tinyint -- A randomized value to determine which subset of printable ASCII characters will be used for the string.
, @String varchar(255)

SET @ID10T = 0
WHILE @ID10T < 100
    BEGIN

    SET @String = ''
        WHILE LEN(@String) < (1+ROUND((254 * RAND(CHECKSUM(NEWID()))),0))
        BEGIN
            SELECT @i = (1 + ROUND((2 * RAND()),0)) -- Randomize which printable character subset is drawn from.
            SELECT @String = @String + ISNULL(CASE WHEN @i = 1 THEN char(48 + ROUND(((57-48)* RAND(CHECKSUM(NEWID()))),0))
            WHEN @i = 2 THEN char(65 + ROUND(((90-65) * RAND(CHECKSUM(NEWID()))),0))
            WHEN @i = 3 THEN char(97 + ROUND(((122-97) * RAND(CHECKSUM(NEWID()))),0))
            END,'-')
        END

    INSERT INTO #tmp_ID10T_Values (ID10T_Value_Set, ID10T_String)
    SELECT 1, @String

    SET @ID10T = @ID10T + 1

    END

-- Demonstrate that IGNORE_DUP_KEY = ON works for primary key index on string-field
 SELECT * FROM #tmp_ID10T_Values


-- Method 1 - Simple INSERT INTO: Expect Approx. (100 row(s) affected)
INSERT INTO #tmp_ID10T_Test (ID10T_String)
SELECT DISTINCT ID10T_String
FROM #tmp_ID10T_Values
GO


-- Method 2 - LEFT OUTER JOIN WHERE NULL to prevent dupes.
--  this is the test case to determine whether the procedure cache is mixing plans
INSERT INTO #tmp_ID10T_Test (ID10T_String)
SELECT DISTINCT T1.ID10T_String
FROM #tmp_ID10T_Values AS T1
LEFT OUTER JOIN #tmp_ID10T_Test AS t2
ON T1.ID10T_String = T2.ID10T_String
WHERE T2.ID10T_Test_ID IS NULL
GO


-- Repeat Method 1: Duplicate key was ignored (0 row(s) affected).
INSERT INTO #tmp_ID10T_Test (ID10T_String)
SELECT DISTINCT ID10T_String
FROM #tmp_ID10T_Values
GO

这似乎不是一个查询计划缓存的问题 - 我应该看到算术错误的方法1个复试,如果这是真的。

-- Repeat Method 1: Expected: Arithmetic overflow error converting IDENTITY to data type tinyint.
INSERT INTO #tmp_ID10T_Test (ID10T_String)
SELECT DISTINCT ID10T_String
FROM #tmp_ID10T_Values
GO

我特别好奇,为什么异常会被抛出。 我可以理解,在方法1中的所有100个独特的值进行测试......所以可以想象查询代理看到的200所记录的二次插入尝试之后潜在的; 我不明白为什么它会第三重复之后看300个记录的潜力 - 在第二次尝试导致了0行,以便顶多会有200个唯一值的潜力。

有人能解释这个吗?

Answer 1:

使用IGNORE_DUP_KEY事件的顺序是:

  1. 记录被用于插入件制备,包括标识值的消耗。 这使得IDENTITY序列上升到200
  2. 记录插入。 IGNORE_DUP_KEY观察和插入都默默地失败

现在你的失败批插入的实际生成的标识值201-300,为此,任何超过255溢出的tinyint列。

这是平凡的运行验证

select ident_current('tmp_ID10T_Test')

宽松整个代码。 因此,对于你的代码,下面的注释:

-- Method 1 - Simple INSERT INTO: Expect Approx. (100 row(s) affected)
   -- ident_current = 1

-- Method 2 - LEFT OUTER JOIN WHERE NULL to prevent dupes.
   -- ident_current = 100
   -- NOTE: The SELECT doesn't produce any rows. No rows to insert

-- Repeat Method 1: Duplicate key was ignored (0 row(s) affected).
   -- ident_current = 200
   -- NOTE: SELECT produced 100 rows, which consumed IDENTITY numbers. Later ignored

-- Repeat Method 1: Expected: Arithmetic overflow error converting IDENTITY to data type tinyint.
   -- ident_current = 255
   -- error raised when IDENTITY reaches 256


文章来源: SQL Arithmetic Overflow for Identity Insert