Android: No Activity found to handle Intent error?

2019-01-17 14:45发布

问题:

No Activity found to handle Intent error? How it will resolve.

Preference customPref = (Preference) findPreference("DataEntryScreen"); 
   customPref
        .setOnPreferenceClickListener(new OnPreferenceClickListener() {
         public boolean onPreferenceClick(Preference preference) {                  

        Intent i = new Intent("com.scytec.datamobile.vd.gui.android.AppPreferenceActivity");
                 startActivity(i);
                  return true;                                        
               }
           });

回答1:

Add the below to your manifest:

  <activity   android:name=".AppPreferenceActivity" android:label="@string/app_name">  
     <intent-filter> 
       <action android:name="com.scytec.datamobile.vd.gui.android.AppPreferenceActivity" />  
       <category android:name="android.intent.category.DEFAULT" />  
     </intent-filter>   
  </activity>


回答2:

in my case, i was sure that the action is correct, but i was passing wrong URL, i passed the website link without the http:// in it's beginning, so it caused the same issue, here is my manifest (part of it)

<activity
        android:name=".MyBrowser"
        android:label="MyBrowser Activity" >
        <intent-filter>
            <action android:name="android.intent.action.VIEW" />
            <action android:name="com.dsociety.activities.MyBrowser" />

            <category android:name="android.intent.category.DEFAULT" />

            <data android:scheme="http" />
        </intent-filter>
    </activity>

when i code the following, the same Exception is thrown at run time :

Intent intent = new Intent();
intent.setAction("com.dsociety.activities.MyBrowser");
intent.setData(Uri.parse("www.google.com"));    // should be http://www.google.com
startActivity(intent);


回答3:

Generally to avoid this kind of exceptions, you will need to surround your code by try and catch like this

try{

// your intent here

} catch (ActivityNotFoundException e) {
// show message to user 
}


回答4:

Intent intent=new Intent(String) is defined for parameter task, whereas you are passing parameter componentname into this, use instead:

Intent i = new Intent(Settings.this, com.scytec.datamobile.vd.gui.android.AppPreferenceActivity.class);
                    startActivity(i);

In this statement replace ActivityName by Name of Class of Activity, this code resides in.