我有一个计时器,ID 1,其具有的TimerProc作为回调函数。
我在做其他的定时器(ID 2,3,...)中的TimerProc和他们使用WM_TIMER
事件,而不是其他的TimerProc。
当创建窗口,我想立刻产生计时器事件,ID 1。
所以我用SendMessage函数一样,
SendMessage(hWnd, WM_TIMER, 1, (LPARAM)&timerproc);
但没有奏效。
如何激活的TimerProc在右侧窗口中的第一次?
void CALLBACK MakeRain(HWND hWnd, UINT iMessage, UINT_PTR wParam, DWORD lParam)
{ /* this is timerproc for ID 1 */
if (gRdx >= MAX_WORDS_COUNT) return;
gRain[gRdx].f = 1;
gRain[gRdx].x = rand() % (gRect.right - 30);
gRain[gRdx].y = 10;
int id = RdxToTID(gRdx);
int vel = rand() % 2000 + 1000;
SetTimer(hWnd, id, vel, NULL); /* In here I am making other timers */
gRdx++;
}
LRESULT CALLBACK WndProc(HWND hWnd, UINT iMessage, WPARAM wParam, LPARAM lParam)
{
HDC hdc;
PAINTSTRUCT ps;
int tid = wParam;
int rdx = TIDToRdx(tid);
switch (iMessage)
{
case WM_CREATE:
GetClientRect(hWnd, &gRect);
srand((unsigned int)time(NULL));
SetTimer(hWnd, 1, MAKE_RAIN_TERM, MakeRain);
/* my trying, It is not working */
//SendMessage(hWnd, WM_TIMER, 1, (LPARAM)&MakeRain);
return 0;
case WM_TIMER:
gRain[rdx].y += 10;
if (gRain[rdx].y >= gRect.bottom) {
gRain[rdx].f = 0;
KillTimer(hWnd, tid);
}
InvalidateRect(hWnd, NULL, TRUE);
return 0;
case WM_PAINT:
hdc = BeginPaint(hWnd, &ps);
for (int i = 0; i < MAX_WORDS_COUNT; i++) {
if (gRain[i].f == 0) continue;
TextOut(hdc, gRain[i].x, gRain[i].y, words[i], lstrlen(words[i]));
}
EndPaint(hWnd, &ps);
return 0;
case WM_DESTROY:
KillTimer(hWnd, 1);
PostQuitMessage(0);
return 0;
}
return DefWindowProc(hWnd, iMessage, wParam, lParam);
}