在IOS JSON的URL解码(URL Decoding of json in ios)

我有其中有浏览器的URL中提到贝尔PHP Web服务1：

http:Domain/webservice/ACTEC_WebService.php?lastupdate=2012-09-01 01:00:00

现在，当我尝试在我的iPhone应用程序来获取URL，它正在这个网址：

http://Domain/webservice/ACTEC_WebService.php?lastupdate=2012-09-01%2001:00:00

这是创建问题。

我已经使用这个代码从我的网址获取数据。

     SBJSON *json = [SBJSON new];
        json.humanReadable = YES;
        responseData = [[NSMutableData data] retain];

        NSString *service = @"";
        NSString *str;
        str = @"LastUpdated";


        NSString *requestString = [NSString stringWithFormat:@"{\"LastUpdated\":\"%@\"}",str];

       // [[NSUserDefaults standardUserDefaults] setValue:nil forKey:@"WRONGANSWER"];

        NSLog(@"request string:%@",requestString);
        NSData *requestData = [NSData dataWithBytes: [requestString UTF8String] length: [requestString length]];


        NSString *fileLoc = [[NSBundle mainBundle] pathForResource:@"URLName" ofType:@"plist"];
        NSDictionary *fileContents = [[NSDictionary alloc] initWithContentsOfFile:fileLoc];
        NSString *urlLoc = [fileContents objectForKey:@"URL"];
        //urlLoc = [urlLoc stringByAppendingString:service];
        NSLog(@"URL : %@",urlLoc);

        NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL: 
                                        [NSURL URLWithString:urlLoc]];  
        NSString *postLength = [NSString stringWithFormat:@"%d", [requestData length]];
        [request setHTTPMethod: @"POST"];
        [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
        [request setHTTPBody:requestData];

        NSError *respError = nil;
        NSData *returnData = [NSURLConnection sendSynchronousRequest: request returningResponse: nil error: &respError ];
        NSString *responseString = [[NSString alloc] initWithData:returnData encoding: NSUTF8StringEncoding];
        NSLog(@"Resp : %@",responseString);

        if (respError) 
        {
            //        NSString *msg = [NSString stringWithFormat:@"Connection failed! Error - %@ %@",
            //                         [respError localizedDescription],
            //                         [[respError userInfo] objectForKey:NSURLErrorFailingURLStringErrorKey]]; 
            UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"ACTEC" 
                                                                message:@"check your network connection" delegate:self cancelButtonTitle:@"OK" 
                                                      otherButtonTitles:nil];
            [alertView show];
            [alertView release];

        } 
        else
        {
......
}

在这里，我得到的URL空响应越来越解码...我怎样才能使这个解决...帮助我。 提前致谢。

Answer 1:

NSString *urlLoc = [[fileContents objectForKey:@"URL"] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; 
NSMutableData *postData = [NSMutableData data];
    NSMutableURLRequest *urlRequest;        
    [postData appendData: [[NSString stringWithFormat: @"add your data which you want to send"] dataUsingEncoding: NSUTF8StringEncoding]];  
    NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
    urlRequest = [[NSMutableURLRequest alloc] init];
    [urlRequest setURL:[NSURL URLWithString:urlLoc]];
    [urlRequest setHTTPMethod:@"POST"];
    [urlRequest setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [urlRequest setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
    [urlRequest setHTTPBody:postData];

    NSString *temp = [[NSString alloc] initWithData:postData encoding:NSUTF8StringEncoding];
    NSLog(@"\n\nurl =%@ \n posted data =>%@",urlLoc, temp);

检查NSLog的。 这里面的数据你寄服务。

NSData *response = [NSURLConnection sendSynchronousRequest:urlRequest returningResponse:nil error:nil];
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
NSLog(@"json_string >> %@",json_string);

也许这会帮助你。

Answer 2:

嘿亲爱的只是一个又一个例子，我刚刚发布我的这个代码..

首先创建新SBJSON解析器对象

SBJSON *parser = [[SBJSON alloc] init];


NSURLRequest *request = [NSURLRequest requestWithURL:
    [NSURL URLWithString:@"http:Domain/webservice/ACTEC_WebService.php?lastupdate=2012-09-01%2001:00:00"]];

执行请求并得到JSON回为一个NSData对象

NSData *response = [NSURLConnection sendSynchronousRequest:request 
    returningResponse:nil error:nil];

获得JSON从NSData的响应的NSString

NSString *json_string = [[NSString alloc] 
    initWithData:response encoding:NSUTF8StringEncoding];

解析JSON响应为对象这里，我们使用NSArray的，因为我们解析JSON状态对象的数组

NSArray *statuses = [parser objectWithString:json_string error:nil]

而在状态数组你有你需要的所有数据。

我希望这可以帮助您...

:)

文章来源: URL Decoding of json in ios