C了解从叉称为多EXEC标准输出(C Read stdout from multiple exec

在处理下面的代码创建一个孩子（ 叉（）），然后孩子们通过调用exec代替本身（）。 在EXEC的标准输出写在一个管道，而不是外壳。然后，父进程从什么EXEC已与同时写入的管道中读取（读（pipefd [0]，缓冲液，的sizeof（缓冲液））！= 0）

谁能告诉我怎么以上，但有孩子的过程（谁与高管更换自己如上）的N多所描述的做同样的事情。

int pipefd[2];
pipe(pipefd);

if (fork() == 0)
{
    close(pipefd[0]);    // close reading end in the child

    dup2(pipefd[1], 1);  // send stdout to the pipe
    dup2(pipefd[1], 2);  // send stderr to the pipe

    close(pipefd[1]);    // this descriptor is no longer needed

    exec(...);
}
else
{
    // parent

    char buffer[1024];

    close(pipefd[1]);  // close the write end of the pipe in the parent

    while (read(pipefd[0], buffer, sizeof(buffer)) != 0)
    {
    }
}

Answer 1:

我找到了答案。我制成管的阵列，使得过程不会覆盖另一个进程的输出。

这里是我的代码。你是否发现任何错误？

#include <signal.h>
#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/time.h>

#define N 10

int main(int argc, char *argv[]) {
    ssize_t readlen;
    int pipefd[N][2];
    int i;
    for (i = 0; i < N; i++) {
        pipe(pipefd[i]);
    }

    int pid = getpid();

    for (i = 0; i < N; i++) {
        if (fork() == 0) //The parent process will keep looping
        {

            close(pipefd[i][0]);    // close reading end in the child

            dup2(pipefd[i][1], 1);  // send stdout to the pipe
            dup2(pipefd[i][1], 2);  // send stderr to the pipe

            close(pipefd[i][1]);    // this descriptor is no longer needed

            char b[50];
            sprintf( b, "%d", i);

            execl("/bin/echo", "echo", b,NULL);


        }
    }

    if (pid == getpid()) {

        // parent

        char buffer[1024];

        for (i = 0; i < N; i++) {
            close(pipefd[i][1]);  // close the write end of the pipe in the parent

            while ((readlen=read(pipefd[i][0], buffer, sizeof(buffer))) != 0)
            {
                        buffer[readlen] = '\0';
            }

            printf("%s\n",buffer);

        }
    }


}

Answer 2:

也许这个代码将做的工作：

const int N = 10; //Number of child processes
int pipefd[2];
pipe(pipefd);
int i;
for (i = 0; i < N; i++) {
    if (fork() == 0) //The parent process will keep looping
    {
        close(pipefd[0]);    // close reading end in the child

        dup2(pipefd[1], 1);  // send stdout to the pipe
        dup2(pipefd[1], 2);  // send stderr to the pipe

        close(pipefd[1]);    // this descriptor is no longer needed

        exec(...);
    }
}

// parent

char buffer[1024];

close(pipefd[1]);  // close the write end of the pipe in the parent

while (read(pipefd[0], buffer, sizeof(buffer)) != 0)
{
}

警告：输出将被混合。如果你想所有进程混合的状态下转储数据，那么你应该管理（公共锁的手段，例如）同步过程。