Command “Print All Lines Starting With” [closed]

问题:

I am looking for a perl command where lines starting with a string are printed. For example, if I wanted to print all lines starting with "1234", what would that command look like? Sed? Awk? Grep?

回答1:

perl -ne 'print if /^1234/' 

or

sed -ne '/^1234/p'

or

awk '/^1234/'

or

grep '^1234'

or

ruby -ne 'print if /^1234/'

or even

python -c 'import fileinput;print "\n".join([l for l in fileinput.input() if l.startswith("1234")])'

回答2:

perl -ne'print if /^1234/' file

But most people would use grep.

grep ^1234 file

Or on Windows

findstr /r ^1234 file

回答3:

For completion:

sed -ne '/^1234/p' somefile
awk '/^1234/{print}' somefile
grep '^1234' somefile