我是比较新的编写SQL。 我有一个要求,我必须显示前5个记录,因为它是和巩固其余为1条单记录,并追加其为公司第六届记录。 我知道前5选择的前5名的记录,但我发现很难把一个逻辑巩固记录的其余部分,并在结果集的底部添加它。
weekof sales year weekno
-------------------------------------------------------------
07/01 - 07/07 2 2012 26
07/08 - 07/14 2 2012 27
07/29 - 08/04 1 2012 30
08/05 - 08/11 1 2012 31
08/12 - 08/18 32 2012 32
08/26 - 09/01 2 2012 34
09/02 - 09/08 8 2012 35
09/09 - 09/15 46 2012 36
09/16 - 09/22 26 2012 37
我想这显示为
weekof sales
----------------------
09/16 - 09/22 26
09/09 - 09/15 46
09/02 - 09/08 8
08/26 - 09/01 2
08/12 - 08/18 32
07/01 - 08/11 6
除了当weekof
跨越年,这会得到你想要的数据,并以正确的顺序:
;WITH x AS
(
SELECT weekof, sales,
rn = ROW_NUMBER() OVER (ORDER BY [year] DESC, weekno DESC)
FROM dbo.table_name
)
SELECT weekof, sales FROM x WHERE rn <= 5
UNION ALL
SELECT MIN(LEFT(weekof, 5)) + ' - ' + MAX(RIGHT(weekof, 5)), SUM(sales)
FROM x WHERE rn > 5
ORDER BY weekof DESC;
当返回跨度的行一年,你可能不得不返回RN以及(和忽略它在表示层):
;WITH x AS
(
SELECT weekof, sales,
rn = ROW_NUMBER() OVER (ORDER BY [year] DESC, weekno DESC)
FROM dbo.table_name
)
SELECT weekof, sales, rn FROM x WHERE rn <= 5
UNION ALL
SELECT MIN(LEFT(weekof, 5)) + ' - ' + MAX(RIGHT(weekof, 5)), SUM(sales), rn = 6
FROM x WHERE rn > 5
ORDER BY rn;
这里的交叉年甚至时显示正确的顺序的替代版本,并且需要单次扫描,而不是两个(重要仅当数据量很大)。 它将在2005年SQL和后续工作:
WITH Sales AS (
SELECT
Seq = Row_Number() OVER (ORDER BY S.yr DESC, S.weekno DESC),
*
FROM dbo.SalesByWeek S
)
SELECT
weekof =
Substring(Min(Convert(varchar(11), S.yr) + Left(S.weekof, 5)), 5, 5)
+ ' - '
+ Substring(Max(Convert(varchar(11), S.yr) + Right(S.weekof, 5)), 5, 5),
sales = Sum(S.sales)
FROM
Sales S
OUTER APPLY (SELECT S.Seq WHERE S.Seq <= 5) G
GROUP BY G.Seq
ORDER BY Coalesce(G.Seq, 2147483647)
;
还有可能的查询可能会非常大的数据集表现得更好,因为它不会(TOP使用一次,而)计算行数。 但是,这是所有的理论没有真正的数据和性能测试:
SELECT
weekof =
Substring(Min(Convert(varchar(11), S.yr) + Left(S.weekof, 5)), 5, 5)
+ ' - '
+ Substring(Max(Convert(varchar(11), S.yr) + Right(S.weekof, 5)), 5, 5),
sales = Sum(S.sales)
FROM
dbo.SalesByWeek S
LEFT JOIN (
SELECT TOP 5 *
FROM dbo.SalesByWeek
ORDER BY yr DESC, weekno DESC
) G ON S.yr = G.yr AND S.weekno = G.weekno
GROUP BY G.yr, G.weekno
ORDER BY Coalesce(G.yr, 9999), G.weekno
;
最终,我真的不喜欢的字符串操作拉出日期范围。 它会更好,如果该表具有MinDate
和MaxDate
作为单独的列,然后创建一个标签,对他们来说就会简单得多。