我写的代码打印出的字符串:“线程0”到“主题4”使用并行线程。
这里是我的代码:
情况1:
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
void *print_message_function(void* parameter) {
long *i = (long *)parameter;
printf("Thread %ld\n", *i);
pthread_exit(0);
}
int main(int argc, char *argv[]) {
pthread_t threads[5];
long i = 0;
for (i = 0; i < 5; i++) {
pthread_create(&threads[i], 0, print_message_function, (void *)&i);
}
pthread_exit(NULL);
}
但结果是:
Thread 2
Thread 3
Thread 3
Thread 4
Thread 5
要么:
Thread 0
Thread 0
Thread 0
Thread 0
Thread 0
它改变了,当我再次运行它。 所以我不知道为什么我传递的值(2-5)或全部(0)或.....(许多情况下)。 我想,我的论点我通过为0〜4。
案例2:
当我更改为新的代码:
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
void *print_message_function(void *parameter);
int main(int argc, char *argv[]) {
pthread_t threads[5];
int i = 0;
for (i = 0; i < 5; i++) {
char *msg = (char*)malloc(sizeof(char));
sprintf(msg, "Thread %d", i);
pthread_create(&threads[i], 0, print_message_function, (void *)msg);
}
}
void *print_message_function(void *parameter) {
printf("%s\n", (char *)parameter);
}
其结果是:
Thread 1
Thread 0
Thread 3
Thread 2
Thread 4
Thread 4
这意味着该循环运行的6倍! 为什么?