给定的字母，获取字母一个字母(Given Letter, Get Next Letter in Al

我有字母 “A”， “B”， “C”。 我想我的结果是“B”，“C”，“d”，在TSQL分别。 请问我用它来实现这一目标？

Answer 1:

使用ASCII得到字符的值，增加一个，并使用CHAR的值转换回一个字符。

SELECT CHAR(ASCII('a') + 1)

Answer 2:

这是你如何做到这一点的第一个字母

DECLARE @myletter char(1) = 'a';
SELECT CHAR(ASCII(@myletter)+1);

Answer 3:

这里是乔纳森·伍德的实施CTE

;WITH cte AS
   (SELECT  CHAR(ASCII('a')) [char], 1 [count]
    UNION ALL
    SELECT  CHAR(ASCII('a') + cte.count) [char], cte.count + 1 [count]
    FROM    cte)
SELECT  TOP(26) cte.count[pos], cte.char
FROM    cte

你可以使用它，就像是和结果插入到表变量或临时表，并用它上。

另一个技巧我也给的，在这个CTE的数据的数据库中的表，那么在未来更容易加入到它，使用它一样，不管出于什么目的或原因。

Answer 4:

3个字母有两个SQL程序alfabetic计数器

（A，B ... Z，AA，AB ... ZY，ZZ，AAA ... ZZZ）：

SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GO

alter procedure letraMas
@letraEntra as char( 1),
@letraSale as char( 1) OUTPUT,
@seLleva as bit  OUTPUT

as

--set @letraEntra = 'w'
--set @letraSale = 'm'
set @seLleva = 0

select
@letraSale = CASE
        WHEN @letraEntra = '' or (@letraEntra is null) or @letraEntra = 'z'
        THEN 'a'
    WHEN @letraEntra < 'z'
        THEN CHAR (ASCII( @letraEntra) + 1)
end

if @letraEntra = 'z' set @seLleva = 1

return

---

SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GO

/* USO:
declare
@tareaEntra as char(3),
@tareaSale as char(3)
set @tareaEntra = 'xzz'
       EXEC tareaMas @tareaEntra, @tareaSale OUTPUT
*/
alter procedure tareaMas
@tareaEntra as char( 3),
@tareaSale as char( 3) OUTPUT

as
declare @charU as char(1 )     -- char de U_nidades albabéticas
declare @charD as char(1 )     -- char de D_ecenas albabéticas
declare @charC as char(1 )     -- char de C_entenas albabéticas
declare @letraSale as char(1 )        -- char de C_entenas albabéticas
declare @seLleva as bit

set @tareaEntra   = right('   ' + rtrim (@tareaEntra), 3)

set @charU = substring(@tareaEntra , 3, 1)
set @charD = substring(@tareaEntra , 2, 1)
set @charC = substring(@tareaEntra , 1, 1)

EXEC letraMas @charU, @letraSale OUTPUT, @seLleva OUTPUT
set @charU = @letraSale
if @seLleva = 1
BEGIN
        EXEC letraMas @charD, @letraSale OUTPUT, @seLleva OUTPUT
        set @charD = @letraSale
        if @seLleva = 1
        BEGIN
               EXEC letraMas @charC, @letraSale OUTPUT, @seLleva OUTPUT
               set @charC = @letraSale
        END
END

set @tareaSale = ltrim(@charC + @charD + @charU)
return

Answer 5:

DECLARE @Letters AS TABLE
(
    Letter CHAR(1)
)
INSERT INTO @Letters
        ( Letter )
VALUES  ( 'A' )
INSERT INTO @Letters
        ( Letter )
VALUES  ( 'B' )
INSERT INTO @Letters
        ( Letter )
VALUES  ( 'C' )
SELECT CHAR(ASCII(Letter) + 1) FROM @Letters

例如使用SQL表变量，但上述任何会为你做它。 取决于你的使用，以明显的整理信件列表什么方法。

文章来源: Given Letter, Get Next Letter in Alphabet