我不是甲骨文的专家,但按照要求,我使用的是Oracle解析器解析XML。 对于下面列出的XML即
<?xml version="1.0" encoding="iso-8859-1" ?>
<SearchOutput>
<rowArray>
<Row>
<cellArray>
<Cell>
<columnId>1</columnId>
<valueArray>
<Value>
<value>IR000024575453</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>5</columnId>
<valueArray>
<Value>
<value>AZ12604823-001</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>2</columnId>
<valueArray>
<Value>
<value>IT06686</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>9</columnId>
<valueArray>
<Value>
<value>Hu Mics Metab K</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>8</columnId>
<valueArray>
<Value>
<value>2006-06-21</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>7</columnId>
<valueArray>
<Value>
<value>2006-07-27</value>
</Value>
</valueArray>
</Cell>
</cellArray>
</Row>
</rowArray>
</SearchOutput>
我已经使用该方法,其中l_xmlclob具有CLOB数据类型和分配上面的XML。
FOR r IN ( SELECT rownum rn, cells
FROM xmltable('/SearchOutput/rowArray/Row' passing XMLTYPE(l_xmlclob)
columns CELLS XMLTYPE PATH './cellArray')
)
LOOP
DBMS_OUTPUT.PUT_LINE('Row: '||r.rn);
FOR c IN ( SELECT colid, colval
FROM xmltable('/cellArray/Cell' passing r.cells
columns COLID NUMBER PATH './columnId',
COLVAL VARCHAR(20) PATH './valueArray/Value/value')
)
LOOP
DBMS_OUTPUT.PUT_LINE('colid, col value: '||c.colid||', '||c.colval);
END LOOP;
END LOOP;
其做工精细,其输出是一样
Row: 1
colid, col value: 1, IR000024575453
colid, col value: 5, AZ12604823-001
colid, col value: 2, IT06686
colid, col value: 9, Hu Mics Metab K
colid, col value: 8, 2006-06-21
colid, col value: 7, 2006-07-27
但问题出现了,如果有两个值一前一后另一个在XML,我想选择第一次出现只即用于下面的XML
<?xml version="1.0" encoding="iso-8859-1" ?>
<SearchOutput>
<rowArray>
<Row>
<cellArray>
<Cell>
<columnId>1</columnId>
<valueArray>
<Value>
<value>Uganda</value>
</Value>
<Value>
<value>Italy</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>5</columnId>
<valueArray>
<Value>
<value>AZ12604823-001</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>2</columnId>
<valueArray>
<Value>
<value>IT06686</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>9</columnId>
<valueArray>
<Value>
<value>Hu Mics Metab K</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>8</columnId>
<valueArray>
<Value>
<value>2006-06-21</value>
</Value>
</valueArray>
</Cell>
<Cell>
<columnId>7</columnId>
<valueArray>
<Value>
<value>2006-07-27</value>
</Value>
<Value>
<value>2012-02-27</value>
</Value>
</valueArray>
</Cell>
</cellArray>
</Row>
</rowArray>
</SearchOutput>
我想“乌干达,AZ12604823-001,IT06686,胡话筒代谢K,2006-06-21,2006-07-27”只内valueArray不是“意大利2012-02-27”进行选择。 但是,不要不知道如何修改现有的代码。