为了节省命令隐形传输点,我有一个HashMap
:
public HashMap<Player, Location> mapHomes = new HashMap<>();
这是访问是这样的:
if(cmd.getName().equalsIgnoreCase("sethome")){
Location loc = player.getLocation();
mapHomes.put(player, loc);
sender.sendMessage("Home set !");
return true;
}
if(cmd.getName().equalsIgnoreCase("home")){
Location loc1 = mapHomes.get(player);
player.teleport(loc1);
sender.sendMessage("Teleported to home");
return true;
}
return false;
由于这些设置应保持在重新启动,我已经实现了一个保存方法:
public void save(HashMap<Player,Location> mapHome, String path) throws NotSerializableException{
try{
ObjectOutputStream oos = new ObjectOutputStream(new FileOutputStream(path));
oos.writeObject(mapHome);
oos.flush();
oos.close();
}catch(Exception e){
e.printStackTrace();
}
}
但它不工作。 它抛出NotSerializableException
。
我认为主要的问题是Player
和Location
不是序列类型,所以我应该怎么办写这个HashMap
?
HashMap
已经是Serializable
。
问题是,在地图内的对象都没有,所以你必须让他们序列化了。
public class SerializedPlayer extends Player implements Serializable {
public SerializedPlayer() {}
public SerializedPlayer(Player playerToClone) {
this.setField1(playerToClone.getField1());
// Set all the fields
}
}
当添加到地图:
map.put(new SerializedPlayer(player), new SerializedLocation(location));
NotSerializableException
当实例需要有一个被抛出Serializable
接口。
class YourClass implements Serializable {
// ...
}
class Player implements Serializable {}
class Location implements Serializable {}
记住,你只能序列化实施的对象Serializable
接口。 所以,你的Player
和Location
类必须实现的接口了。
我觉得你写HashMap<Player, Location>
到文件。
什么,你需要做的就是让你的Player
和Location
类的序列化。
public class Player implements java.io.Serializable {
// ...
}
public class Location implements java.io.Serializable {
// ...
}
HashMap
是序列化的。
为了让Location
可序列化,我建议使用这个类 。 我自己写的,只是请你给我的信用代码。
package com.github.JamesNorris.Class;
import java.io.Serializable;
import java.util.HashMap;
import java.util.Map;
import org.bukkit.Bukkit;
import org.bukkit.Location;
import org.bukkit.Server;
import org.bukkit.World;
/**
* The class that allows location to be serialized, and be used
* in a file. This class should not be changed, otherwise it
* will not work for older files.
*
* @author Jnorr44
*/
public final class SerializableLocation implements Serializable {
private static final long serialVersionUID = 8650311534439769069L;
private final String world;
private final String uuid;
private final double x, y, z;
private final float yaw, pitch;
private transient Location loc;
/**
* Creates a new SerializableLocation instance of any org.bukkit.Location.
*
* @param l
*/
public SerializableLocation(Location l) {
this.world = l.getWorld().getName();
this.uuid = l.getWorld().getUID().toString();
this.x = l.getX();
this.y = l.getY();
this.z = l.getZ();
this.yaw = l.getYaw();
this.pitch = l.getPitch();
}
/**
* Gets the org.bukkit.Location back from any SerializableLocation.
*
* @param l
* @return
*/
public static Location returnLocation(SerializableLocation l) {
float pitch = l.pitch;
float yaw = l.yaw;
double x = l.x;
double y = l.y;
double z = l.z;
World world = Bukkit.getWorld(l.world);
Location location = new Location(world, x, y, z, yaw, pitch);
return location;
}
// FROM HERE ON NEEDS DOC NOTES
public SerializableLocation(Map<String, Object> map) {
this.world = (String) map.get("world");
this.uuid = (String) map.get("uuid");
this.x = (Double) map.get("x");
this.y = (Double) map.get("y");
this.z = (Double) map.get("z");
this.yaw = ((Float) map.get("yaw")).floatValue();
this.pitch = ((Float) map.get("pitch")).floatValue();
}
public final Map<String, Object> serialize() {
Map<String, Object> map = new HashMap<String, Object>();
map.put("world", this.world);
map.put("uuid", this.uuid);
map.put("x", this.x);
map.put("y", this.y);
map.put("z", this.z);
map.put("yaw", this.yaw);
map.put("pitch", this.pitch);
return map;
}
public final Location getLocation(Server server) {
if (loc == null) {
World world = server.getWorld(this.uuid);
if (world == null) {
world = server.getWorld(this.world);
}
loc = new Location(world, x, y, z, yaw, pitch);
}
return loc;
}
}
现在简单地做:
SerializableLocation loc = new SerializableLocation(LOCATION);
这是必需的原因是因为Location
包含world
, x
, y
, z
, yaw
和pitch
,其中world
是不可序列。
事实上,你正在试图序列Player
和Location
,努力实现新的课程等,但你为什么要这么做?
如果你不保存这将是更好的Player
和Location
的对象,但他们的字符串表示来代替。 例如,你可以使用Player.getName()
和类似"world:100:65:100"
的位置(所以我们可以很容易地得到所有数据回来String.split(":")
我认为这是一个更好的方法。