Flatten xml hierarchy using XSLT

问题:

I would like to convert a nested xml to flatten xml using XSLT.

Incoming xml Structure would be similar but the node names would change for the incoming xmls, so would like to handle in dynamically

Sample input

<?xml version="1.0" encoding="UTF-8"?>
<queryResponse>
  <Account>
    <Id>0010</Id>
    <Name>AA</Name>
    <RecordTypeId>0122/RecordTypeId>
    <RecordType>
      <Id>012</Id>
      <DeveloperName>Legal_Associate</DeveloperName>
    </RecordType>
  </Account>
  <Account>
    <Id>0011</Id>
    <Name>BB</Name>
    <RecordTypeId>0123</RecordTypeId>
    <RecordType>
      <Id>013</Id>
      <DeveloperName>Legal_Associate</DeveloperName>
    </RecordType>
  </Account>
 </queryResponse>

Expected Output

<?xml version="1.0" encoding="UTF-8"?>
<queryResponse>
  <Account>
    <Id>0010</Id>
    <Name>AA</Name>
    <RecordTypeId>0122</RecordTypeId>
    <RecordType.Id>012</RecordType.Id>
  <RecordType.DeveloperName>Legal_Associate</RecordType.DeveloperName>
  </Account>
  <Account>
    <Id>0011</Id>
    <Name>BB</Name>
    <RecordTypeId>0123<RecordTypeId>
    <RecordType.Id>013</RecordType.Id>    <RecordType.DeveloperName>Legal_Associate</RecordType.DeveloperName>
    </Account>
    </queryResponse>

回答1:

While posting the question you should post the tried code as well hense we can tell you the updation.

Here is the code which you can achive your answer:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 
    exclude-result-prefixes="xs" version="2.0">

    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="RecordType">
        <xsl:for-each select="*">
            <xsl:element name="{concat(name(..),'.',name())}">
                <xsl:apply-templates select="node()"/>
            </xsl:element>
        </xsl:for-each>
    </xsl:template>

</xsl:stylesheet>