I was wondering if someone could give me a direction on how to give functions to a file... This is a bit hard to explain, so I'll try my best.
Let's say I have an application (using wxPython) and let's say that I have a file. Now this file is assigned to open with the application. So, I double-click the file and it opens the application. Now my question is, what would have to be written on the file to, for example, open up a dialog? So we double-click the file and it opens a dialog on the application?
PS: I know that I have first to associate the program with a certain file type to double-click it, but thats not the question.
AFAIK most platforms just call the helper app with the file you clicked on as an argument, so your filepath will be in sys.argv[1]
I think what he wants to do is associate a file extension to his application so when he opens the file by double clicking it, it sends the contents of the file to his app; in this case, display the contents within a Dialog?
If this is the case, than the first thing you would need to do (provided you are on windows) is create the appropriate file association for your file extention. This can be done through the registry and when setup correctly will open your app with the the path/filename of the file that was executed as the first argument. Ideally it is the same as executing it from the command line like:
C:\your\application.exe "C:\The\Path\To\my.file"
Now as suggested above, you would then need to use sys.argv to to obtain the arguments passed to your application, in this case C:\Path\To\my.file would be the first argument. Simply put, sys.argv is a list of arguments passed to the application; in this case the first entry sys.argv[0] will always be the path to your application, and as mentioned above, sys.argv[1] would be the path to your custom file.
Example:
import sys
myFile = sys.argv[1]
f = file(myFile, "r")
contents = f.read()
f.close()
Then you will be able to pass the variable contents to your dialog to do whatever with.
