We suffered some kind of invasion in our SQL Server.
I'm trying to find in every database, in every table, every column the word abortion
and cheat
.
I can do this with this query, but in a single database.
-- Store results in a local temp table so that. I'm using a
-- local temp table so that I can access it in SP_EXECUTESQL.
create table #tmp
(
db varchar(max),
tbl nvarchar(max),
col nvarchar(max),
val nvarchar(max),
);
declare @db nvarchar(max);
declare @tbl nvarchar(max);
declare @col nvarchar(max);
declare @q nvarchar(max);
declare @search nvarchar(max) = 'abortion';
-- Create a cursor on all columns in the database
declare c cursor for
SELECT
DB_NAME(DB_ID()) as DBName, tbls.TABLE_NAME, cols.COLUMN_NAME
FROM INFORMATION_SCHEMA.TABLES AS tbls
JOIN INFORMATION_SCHEMA.COLUMNS AS cols ON tbls.TABLE_NAME = cols.TABLE_NAME
-- For each table and column pair, see if the search value exists.
open c
fetch next from c into @db, @tbl, @col
while @@FETCH_STATUS = 0
begin
-- Look for the search key in current table column and if found add it to the results.
SET @q = 'INSERT INTO #tmp SELECT ''' +@db+''',''' + @tbl + ''', ''' + @col + ''', ' + @col + ' FROM ' + @tbl + ' WHERE ' + @col + ' LIKE ''%' + @search + '%'''
EXEC SP_EXECUTESQL @q
fetch next from c into @db, @tbl, @col
end
close c
deallocate c
-- Get results
select distinct db,tbl,col from #tmp
-- Remove local temp table.
drop table #tmp
How can I find these strings? The result set should be:
DATABASE | TABLE | COLUMN
I don't need the result ( text field ), and I need to select distinct
for tables and columns, because it will be a lot of abortion
in the same table/column.