一个时隙的多个信号(multiple signals for one slot)

2019-09-19 02:36发布

对于我的GUI我想有两对上下了scrollarea滚动按钮。 第一组按钮应该说scrollarea1工作,第二组按钮应在scrollarea2工作。 我把在scrollarea窗口小部件被称为viewport1和viewport2。 由于这两个都设置按钮也应该这样做(上下滚动),我想我会做两个插槽称为scrollUp和下滚,将处理滚动两个按钮组。 不幸的是,我不能做这项工作,需要一些帮助。 我曾尝试以下:

QPushButton up;
QPushButton down;
QPushButton up2;
QPushButton down2;

connect(&up,SIGNAL(clicked()),&up,SLOT(scrollUp()));
connect(&up2,SIGNAL(clicked()),&up,SLOT(scrollUp()));
connect(&down,SIGNAL(clicked()),&down,SLOT(scrollDown()));
connect(&down2,SIGNAL(clicked()),&down,SLOT(scrollDown()));

void MainWindow::scrollDown()
{
QScrollArea area;
QWidget view;

if((QPushButton) &sender = down)
{
    area=scrollArea;
    view=viewport;
}
if((QPushButton) &sender = down2)
{
    area=scrollArea;
    view=viewport;
}
int curpos = area.verticalScrollBar()->value();
area.verticalScrollBar()->setValue(curpos+15);
int newpos = area.verticalScrollBar()->value();
QPoint topLeft = area.viewport()->rect().topLeft();
view.move(topLeft.x(),topLeft.y()-(newpos));
}

void MainWindow::scrollUp()
{
QScrollArea area;
QWidget view;

if((QPushButton) &sender = up)
{
    area=scrollArea;
    view=viewport;
}
if((QPushButton) &sender = up2)
{
    area=scrollArea2;
    view=viewport2;
}
int curpos = area.verticalScrollBar()->value();
area.verticalScrollBar()->setValue(curpos-15);
int newpos = area.verticalScrollBar()->value();
QPoint topLeft = area.viewport()->rect().topLeft();
view.move(topLeft.x(),topLeft.y()-(newpos));
}

但是,有几个原因此doesn't工作。 我也试过给插槽一些参数,是这样的:

connect(&up,SIGNAL(clicked()),&up,SLOT(scrollUp(scrollarea1,viewport1)));
connect(&up2,SIGNAL(clicked()),&up,SLOT(scrollUp(scrollarea2,viewport2)));

但同样,没有更迭。 有谁能够帮助我?

Answer 1:

首先,“它不工作”并不意味着什么,这是很难帮助你,如果你不说你得到了什么错误。 然后,还有一些问题。

所有的QObject的派生类没有可复制的,这意味着你不能做

QWidget a;
QWidget b;
b = a; // Wrong

您应该使用指针(或者引用)。

QWidget a;
QWidget * b = new QWidget(...);
QWidget * c;
c = & a; // Ok
c = b; // Ok

然后您connect电话是错误的:

connect(&up, SIGNAL(clicked()), &up, SLOT(scrollUp()));

第三个参数是谁拥有插槽的对象。 up是一个QPushButton,它不具有scrollUp()插槽,它是你的主窗口谁做:

connect(&up, SIGNAL(clicked()), this, SLOT(scrollUp()));

(因为connect被称为在主窗口的构造this指向当前主窗口对象)。

此外,在C ++单=标志表示分配,是否相等的比较使用=='. And =='. And sender`是一个函数。

如果以正确的方式来实现你的方法应该工作:

class MainWindow: public QWidget
{
    QScrollArea * scroll1;
    QScrollArea * scroll2;
    QWidget * view1;
    QWidget * view2;
    QPushButton * up1;
    QPushButton * up2;
    QPushButton * down1;
    QPushButton * down2;

public:
    MainWindow()
    {
        // Here initialize member variables.
        ...

        connect(up1, SIGNAL(clicked()), this, SLOT(scrollUp()));
        connect(up2, SIGNAL(clicked()), this, SLOT(scrollUp()));
        connect(down1, SIGNAL(clicked()), this, SLOT(scrollDown()));
        connect(down2, SIGNAL(clicked()), this, SLOT(scrollDown()));
    }

public slots:
    void scrollDown()
    {
        QScrollArea * area;
        QWidget * view;

        if(qobject_cast<QPushButton>(sender()) == down1) {
            area = & scroll1;
            view = & view1;
        } else if(qobject_cast<QPushButton>(sender()) == down2) {
            area = & scroll2;
            view = & view2;
        } else {
            // Error.
        }

        // Now `area` and `view` point to the right widgets.
        ...
    }

    void scrollUp()
    {
        // The same as before.
    }
};

另一种方法是将提取实际的滚动指令到一个单独的功能:

class MainWindow: public QWidget
{
    // Same variables as before
    ...

public:
    MainWindow()
    {
        // Here initialize member variables.
        ...

        connect(up1, SIGNAL(clicked()), this, SLOT(scrollUp1()));
        connect(up2, SIGNAL(clicked()), this, SLOT(scrollUp2()));
        connect(down1, SIGNAL(clicked()), this, SLOT(scrollDown1()));
        connect(down2, SIGNAL(clicked()), this, SLOT(scrollDown2()));
    }

public slots:
    void scrollDown(QScrollArea * area, QWidget * view)
    {
        // Here you scroll over `area` and `view`.
    }

    void scrollDown1()
    {
        scrollDown(scroll1, area1);
    }

    void scrollDown2()
    {
        scrollDown(scroll2, area2);
    }

    // Again, the same for `scrollUp`.
};


Answer 2:

有在你的代码的几个误区:

  • 关于信号的发送者:没有一个QObject所谓的“ sender ”,而是一种方法QObject * QObject::sender() const; 它返回该信号的发送者的指针。
  • 在if条件:你是铸造QPushButton**QPushButton(QPushButton) &sender ),你不要比较你的按钮那个东西up(2)down(2)
  • 在插槽和信号之间的连接:在scrollUpscrollDown插槽不属于QPushButton类,但你的MainWindow类。

最后,你应该写这样的事情:

connect(&up,    SIGNAL(clicked()), this, SLOT(scrollUp()));
connect(&up2,   SIGNAL(clicked()), this, SLOT(scrollUp()));
connect(&down,  SIGNAL(clicked()), this, SLOT(scrollDown()));
connect(&down2, SIGNAL(clicked()), this, SLOT(scrollDown()));

void MainVindow::scrollDown() {
    // [...]

    QPushButton * senderButton = qobject_cast<QPushButton *>(this->sender()); 
    // QPushButton * senderButton = (QPushButton *) this->sender(); works too

    if (senderButton == &down) {
        // [...]
    }

    if (senderButton == &down2) {
        // [...]
    }

    // [...]
}

void MainVindow::scrollUp() {
    // [...]

    QPushButton * senderButton = qobject_cast<QPushButton *>(this->sender());
    // QPushButton * senderButton = (QPushButton *) this->sender(); works too

    if (senderButton == &up) {
        // [...]
    }

    if (senderButton == &up2) {
        // [...]
    }
    // [...]
}


Answer 3:

首先插槽可以没有其他参数比信号手吧。 被点击的没有参数,有前槽可以没有参数。

我认为,最简单的方法来检查scrollArea 1或2是否已经集中,并从其中一个应该移动决定。

我还认为,有你的代码中的错误。 不应该这样:

if((QPushButton) &sender = down2)
{
    area=scrollArea;
    view=viewport;
}

是这样的:

if((QPushButton) &sender = down2)
{
    area=scrollArea2;
    view=viewport2;
}


Answer 4:

首先,这是伪代码。 它不会编译,但它应该包含必要的信息。

我相信这个问题可以通过QSignalMapper类中最优雅的解决。 它允许从多个发送者参数的信号,以连接到一个时隙。

在标题中写的是这样的:

class QSignalMapper;

class MainWindow : public QMainWindow
{

public:
  void init();

public slots:
  void handleScrollButtons(int id);

private:
enum { ScrollUp1, ScrollDown1, ScrollUp2, ScrollDown2 } // just makes it more convenient to use

QSignalMapper *m_scrollbuttonhandler;
}

在源文件中,写这样的事情

#include <QSignalMapper>

void MainWindow::init()
{
  m_scrollbuttonhandler = new QSignalMapper(this);
  m_scrollbuttonhandler->setMapping(scrollup1button, ScrollUp1);
  m_scrollbuttonhandler->setMapping(scrolldown1button, ScrollDown1);
  m_scrollbuttonhandler->setMapping(scrollup2button, ScrollUp2);
  m_scrollbuttonhandler->setMapping(scrolldown2button, ScrollDown2);
  connect(scrollup1button, SIGNAL(clicked(bool)), m_scrollbuttonhandler, SLOT(map()));
  connect(scrolldown1button, SIGNAL(clicked(bool)), m_scrollbuttonhandler, SLOT(map()));
  connect(scrollup2button, SIGNAL(clicked(bool)), m_scrollbuttonhandler, SLOT(map()));
  connect(scrolldown2button, SIGNAL(clicked(bool)), m_scrollbuttonhandler, SLOT(map()));

  connect(m_scrollbuttonhandler, SIGNAL(mapped(int)), this, SLOT(handleScrollButtons(int)));
}

void MainWindow::handleScrollButtons(int id)
{
  switch (id)
  {
    case ScrollUp1:
    // stuff to do for scrollup1button
    case ScrollDown1:
    // stuff to do for scrolldown1button
    case ScrollUp2:
    // stuff to do for scrollup2button
    case ScrollDown2:
    // stuff to do for scrolldown2button
  }
}


文章来源: multiple signals for one slot