为什么`VECTOR`实现有多种情况?(Why does `vector` implementati

2019-09-19 02:46发布

下面是Clojure的定义vector

(defn vector
  "Creates a new vector containing the args."
  {:added "1.0"
   :static true}
  ([] [])
  ([a] [a])
  ([a b] [a b])
  ([a b c] [a b c])
  ([a b c d] [a b c d])
  ([a b c d & args]
     (. clojure.lang.LazilyPersistentVector (create (cons a (cons b (cons c (cons d args))))))))

为什么有这么多的情况下? 或者,如果有这么多,为什么没有更多?

我的猜测是,它引人注目的执行效率与概率之间的平衡,但我不太看不出这会更有效。

Answer 1:

4似乎在效率的时候有很多的争论,当没有很多参数之间的平衡。

举个例子:

(defn vector-few
  ([] [])
  ([ & args ] (. clojure.lang.LazilyPersistentVector (create args))))


(defn vector-many
  ([] [])
  ([a] [a])
  ([a b] [a b])
  ([a b c] [a b c])
  ([a b c d] [a b c d])
  ([a b c d e] [a b c d e])
  ([a b c d e f] [a b c d e f])
  ([a b c d e f & args] (. clojure.lang.LazilyPersistentVector (create (cons a (cons b (cons c (cons d (cons e (cons f args))))))))))

运行具有4个元件的测试:

=> (time (dotimes [x 1000000] (vector 1 2 3 4)))
"Elapsed time: 12.082104 msecs"

=> (time (dotimes [x 1000000] (vector-few 1 2 3 4)))
"Elapsed time: 443.056339 msecs"

=> (time (dotimes [x 1000000] (vector-many 1 2 3 4)))
"Elapsed time: 11.812106 msecs"

然后用5:

=> (time (dotimes [x 1000000] (vector 1 2 3 4 5)))
"Elapsed time: 467.904979 msecs"

=> (time (dotimes [x 1000000] (vector-few 1 2 3 4 5)))
"Elapsed time: 537.080198 msecs"

=> (time (dotimes [x 1000000] (vector-many 1 2 3 4 5)))
"Elapsed time: 10.30695 msecs"

并用8(因此所有的功能都使用var-ARGS情况下):

=> (time (dotimes [x 1000000] (vector 1 2 3 4 5 6 7 8)))
"Elapsed time: 832.803266 msecs"

=> (time (dotimes [x 1000000] (vector-few 1 2 3 4 5 6 7 8)))
"Elapsed time: 689.526288 msecs"

=> (time (dotimes [x 1000000] (vector-many 1 2 3 4 5 6 7 8)))
"Elapsed time: 905.95839 msecs"


文章来源: Why does `vector` implementation have multiple cases?