How to read 2 lines of integer input in C?

问题:

I'm doing a project for my algorithms class and I'm having a lot of trouble with inputs. I'm trying to read an input like this:

6 0 2 3 1 3
5 9 2 1 3

The integers will need to go to

int num1; // num1 = 6
int num2; // num2 = 5
int array1[100]; // array1 = {0, 2, 3, 1, 3, 0, 0, ...}
int array2[100]; // array2 = {9, 2, 1, 3, 0, 0, ...}

The input will come from standard input, in the form of a file. So in terminal running the program would look like this:

cat input.txt | ./a.out

Where input.txt contains the two lines of integers.

Here is my flawed attempt so far:

while(scanf("%d%c", &temp, &ch) > 1){
    if (ch != '\n'){
        one[count] = temp;
    } 
    else if (ch == '\n'){
        count = 0;
        two[count] = temp;

    }
    one[count] = temp;
    count++;
    if (ch != ' ')
    {
        printf("Invalid input. Please do int + space.\n");
        return -1;
    }
    if ((temp >= 100) || (temp <= -100))
    {
        printf("Input is too big, must be between -100, 100.\n");
        return -1;
    }
    if (one[0] < 1){
        printf("Input for n cannot be smaller than one!");
        return -1;
    }
}

I think the main issue is that I'm just not sure how to deal with multiple lines of input. One line of input is fine by me but multiple lines is what trips me over.

回答1:

You could fetch an entire line of input using the getline function and then iterate over that line, scanning one number at a time using the strtol function.

From the example in your question I assume that you want all remaining entries in the two arrays to be zero so don't forget to zero them out (either manually or using the memset function.).

And also don't forget to free() the buffer getline gave you.

回答2:

Look at my code below. Maybe it helps you.

Generally if you know how many numbers will be inputted, you can read numbers one by one using scanf("%d", ...) and use fflush() when expected amount is met to clear any other numbers in buffer.

int main()
{
    int it;
    int it1 = 0;
    int it2 = 0;
    int line1[100];
    int line2[100];

    scanf("%d", &it1); // amount of line 1 numbers
    scanf("%d", &it2); // amount of line 2 numbers

    it = 0;
    do
    {
        scanf("%d", &line1[it]);
    } while (++it < it1);

    fflush(stdin); // clear input buffer

    it = 0;
    do
    {
        scanf("%d", &line2[it]);
    } while (++it < it2);

    return 0;
}

回答3:

Actually I ended up using scanf, here is the working code below. It really helped to read some of these comments and also refer to K&R

#include <stdio.h>
#include <string.h>

#define ARRAY_SIZE  100

void shiftArrayBackByOne(int a[]){
    for(int i = 1; i <= ARRAY_SIZE; i++){
        a[i - 1] = a[i];
    }
}

void printArray(int a[], int n){
    for(int i = 0; i < n; i++){
        printf("%d ", a[i]);
    }
    putchar('\n');
}

int main(){
    int isLineTwo = 0;
    int countOne = 0;
    int countTwo = 0;
    int inputNum;
    int num1;
    int num2;
    int array1[ARRAY_SIZE];
    int array2[ARRAY_SIZE];

    char ch;

    while(scanf("%d%c", &inputNum, &ch) > 0){

        //Puts the input into different arrays depeding
        //on value of isLineTwo
        if (isLineTwo){
            array2[countOne] = inputNum;
            countOne++;
        } else {
            array1[countTwo] = inputNum;
            countTwo++;
        }

        //Increment isLineTwo if ch is a 'newline'
        if (ch == '\n')
        {
            isLineTwo++;
        }

        //Check if user inputs more than 2 lines
        if (isLineTwo > 1){
            printf("Hey, no more than 2 input lines!\n");
        }

    }
    printArray(array1, countOne);
    printArray(array2, countTwo);

    num1 = array1[0];
    num2 = array2[0];

    shiftArrayBackByOne(array1);
    shiftArrayBackByOne(array2);

    printf("num1 = %d\n", num1);
    printf("num2 = %d\n", num2);

    printArray(array1, countOne);
    printArray(array2, countTwo);
}