移动对象（元件）一个升压使用Javascript(Move an object (element)

我有几个对象是这样的：

我想移动type和value一步起来，使他们旁边会field ，然后删除data 。
它看起来像这样当departments转换为JSON：

[
    {"field"    : "DEPARTMAN_NO",
     "data"     : { "type":"numeric" , "comparison":"eq" , "value":11 }
    },
    {"field"    : "DEPARTMAN_ADI",
     "data"     : { "type":"string" , "value":"bir" }
    }
]

我努力了：

departments = grid.filters.getFilterData();
i = {};
for(var i in department) {
department = i.data;
delete.department.data;
};

但忽略了最低的工作。

Answer 1:

1）首先，循环departments ，每个项目我们称之为department ;
2）你要移到department.data的性能department ，从另一个角度来看，你可以移动department的性质department.data并返回department.data ，这样的代码：

var departments = [{
        "field": "DEPARTMAN_NO",
        "data": {
            "type": "numeric",
            "comparison": "eq",
            "value": 11
        }
    }, {
        "field": "DEPARTMAN_ADI",
        "data": {
            "type": "string",
            "value": "bir"
        }
    }],
    department;

for (var i = 0, len = departments.length; i < len; i++) {
    department = departments[i]; // department
    for (var key in department) {
        if (key !== 'data' && department.data) {
            department.data[key] = department[key];
        }
    }
    departments[i] = department.data || department; // if no department.data, no change
}

console.log(departments);

结果：

查看完整的演示http://jsfiddle.net/KVYE5/

Answer 2:

department.type = department.data.type;
department.value = department.data.value;
delete department['data'];

Answer 3:

obj =
[
    {"field"    : "DEPARTMAN_NO",
     "data"     : { "type":"numeric" , "comparison":"eq" , "value":11 }
    },
    {"field"    : "DEPARTMAN_ADI",
     "data"     : { "type":"string" , "value":"bir" }
    }
];


for ( var item in obj ) {
    if ( obj[item].field && obj[item].data ) { //check the 'field' and 'data' exist
        obj[item].field = {
            dept : obj[item].field ,         //department name is put into a property
            type : obj[item].data.type,      //so is data.type and data.value..
            value: obj[item].data.value      //..all are now contained in 'field'
        };
        delete obj[item].data;               //remove the 'data' object
    }
}

console.log(obj);

Answer 4:

我写了一个小NPM包，做你问什么：移动属性了一个对象的水平。

你可以在这里得到它： https://www.npmjs.com/package/move-property-up-a-level

用法

var movePropertyUpALevel = require('movePropertyUpALevel');

var fakeObj = {
    poodle: {
        first: {
            hey: 'you'
        },
        second: 'meAgain'
    }
};

movePropertyUpALevel(fakeObj, 'poodle');

console.log(fakeObj.first.hey);
//'you'
console.log(fakeObj.poodle);
//undefined

文章来源: Move an object (element) one step up with Javascript